1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
denis-greek [22]
3 years ago
8

Solve x2 - 8x + 14 = 2x - 7

Mathematics
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

x=7, x=3

Step-by-step explanation:

             x^{2} -8x+14=2x-7

x^{2} -8x-2x+14+7=0

            x^{2} -10x+21=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x= \frac{-b\pm \sqrt{b^2-4ac}}{2a}

positive

x=\frac{-\left(-10\right)+\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=7

negative

x=\frac{-\left(-10\right)-\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=3

You might be interested in
What fraction is <br><br>4 hours of a day<br><br>45 mins of an hour<br><br>240cm3 of a litre​
lesya [120]

4 hours of a day

1/6

45 mins of an hour

3/4

240cm3 of a litre​liter

240cm3=0.24l

6/25

8 0
3 years ago
Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confide
ioda

Answer:

The question is incomplete, but the step-by-step procedures are given to solve the question.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{\sigma}{\sqrt{n}}

The lower end of the interval is the sample mean subtracted by M.

The upper end of the interval is the sample mean added to M.

The 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (lower end, upper end).

7 0
3 years ago
Barry read for 15 more minutes than Robert.
Greeley [361]
Hi!

C. v + 15

Barry read for 15 MORE minutes than Robert.
6 0
3 years ago
How many minutes are there in 4 and a half hours?
Annette [7]
1 \ hour=60 \ minutes \\\\ a \ half \ an \ hour = \frac{1 \ hour}{2}=\frac{60min}{2}=30 minutes \\\\ 4 \ hurs \ and \ a half = 4*60+30= \\\\ =240+30=\\\\ =\boxed{270}
7 0
3 years ago
Read 2 more answers
Please help <br> And do step by step plz and thank you
Law Incorporation [45]

Answer:

Each child gets 3/2 cookies

Step-by-step explanation:

3/2=1.5 therefore they both get 1.5 or 1 and a half cookies each. 1.5= 3/2

Hope you find this helpful. I am happy to help you whenever I can.

3 0
3 years ago
Other questions:
  • Out of 200 bulbs in a box, 12 bulbs are defective. One bulb is taken out at random from the box. What is the probability that th
    8·1 answer
  • Kyra observed that 85% of the students at a library liked reading mystery stories. If 30 students at the library did not like re
    13·1 answer
  • Find the volume of the cylinder use 3.14 for pie. Round to the nearest tenth
    13·1 answer
  • there are 3 second grade classes at the sunshine school one has 22students and another has 20 students if there are 63 students
    5·2 answers
  • Find the indicated value. Use either half angle formulas or sum and difference formulas.
    6·1 answer
  • Can you help me put them from greatest to least
    11·2 answers
  • Please help me with any of these questions
    15·1 answer
  • What is the root of 105 to 2 decimal places
    13·1 answer
  • What is the value of x<br>1. 124<br>2. 62<br>3. 112<br>4. 68<br>explain why the answer is correct ​
    9·2 answers
  • The sum of two times a number and 7 is five times the difference of a number and six. Solve for the variable then Round your ans
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!