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Serga [27]
2 years ago
15

Prove the equation, you can only change one side csc0-sin0=cot0cos0

Mathematics
1 answer:
Tom [10]2 years ago
5 0

\textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ csc(\theta )-sin(\theta )~~ = ~~cot(\theta )cos(\theta ) \\\\[-0.35em] ~\dotfill\\\\ csc(\theta )-sin(\theta )\implies \cfrac{1}{sin(\theta )}-sin(\theta )\implies \cfrac{1~~ - ~~sin^2(\theta )}{sin(\theta )} \\\\\\ \cfrac{cos^2(\theta )}{sin(\theta )}\implies \cfrac{cos(\theta )}{sin(\theta )}\cdot cos(\theta )\implies cot(\theta )cos(\theta )

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Write -72=2y^2-16y-20x in standard form
kifflom [539]

Answer:

-72=-12y-20x

Step-by-step explanation:

-72=2y^2-16y-20x

square the 2 keeping the variable

-72=4y-16y-20x

Then combine like terms in this case the numbers followed by y's

-72=-12y-20x

This is the standard form as there is nothing else you can combine to break this down any further

5 0
3 years ago
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What is a trick for multiplying 9`s
Dovator [93]
A trick that is good for multiplying 9's is, remember that each time the tens digit changes the number in the ones spaces minuses 1. If you don't understand what I am saying look at the following:- 

9
18
27
36
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See the pattern? In the tens place you need to add 1 and in the tens place you need to subtract by 1.

Hope I helped ya!! xD
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3 years ago
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The area of a rectangle is 84 inches. It has a length of x−2 and a width of x+3. What are the dimensions of the rectangle?
gayaneshka [121]
Call the width of the rectangle x. Call the length of the rectangle x + 2. The area of the rectangle would be the length times the width. We know this is 15 square inches. Set up the equation and solve for x.

(x +2)x = 15
x2 + 2x = 15
x2 + 2x - 15 = 0
Factor the quadratic equation:
(x - 3)(x + 5) = 0
x = 3 or x = -5
Since length can't be negative, discard the answer -5.
If x = 3, then the width is 3 and the length is x + 2 or 5. 5 x 3 = 15 which equals the area.
3 0
4 years ago
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10 POINTS + BRAINLIEST ANSWER!!
svp [43]
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8 0
4 years ago
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Analyze the diagram below and answer the question that follows.
Anna35 [415]

Answer:

The right statement is sin(J) = cos(L) ⇒ answer D

Step-by-step explanation:

* Lets describe the figure

- LKJ is a right triangle, where K is a right angle

∵ m∠K = 90°

∵ LJ is opposite to angle K

∴ LJ is the hypotenuse

∵ LJ = 219

∵ KJ = 178

- By using Pythagoras Theorem

∵ (LJ)² = (LK)² + (KJ)²

∴ (219)² = (LK)² + (178)² ⇒ subtract (178)² from both sides

∴ (LK)² = (219)² - (178)²

∴ (LK)² = 16277

∴ LK = √16277 = 127.58

* Lets revise how to find the trigonometry function

# sin Ф = opposite/hypotenuse

# cos Ф = adjacent/hypotenuse

# tan Ф = opposite/adjacent

∵ LK is the opposite side to angle J

∵ LJ is the hypotenuse

∵ sin(J) = LK/LJ

∵ LK = 127.58 , LJ = 219

∴ sin(J) = 127.58/219 = 0.583

∵ LK is the adjacent side to angle L

∵ LJ is the hypotenuse

∵ cos(L) = LK/LJ

∵ LK = 127.58 , LJ = 219

∴ cos(L) = 127.58/219 = 0.583

∴ sin(J) = cos(L)

* The right statement is sin(J) = cos(L)

7 0
3 years ago
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