The third one/upper right graph (bc it passes the vertical line test)
To determine if the amount of lace is enough to be placed around the tablecloth, we determine the circumference of the tablecloth through the equation,
C = 2πr
where C is circumference,
r is the radius
Substituting the known values,
C = 2π(3 ft) = 18.85 ft
Hence, the 15 ft lace will not be enough for the tablecloth.
Answer: B. h = 7.5 cm ; r = 10 cm
Given:
Cylinder
Cone
Volume of Cylinder = π r² h
= 3.14 * (5cm)² * 15cm
= 3.14 * 25cm² * 15cm
= 1,177.50 cm³
Volume of the cone = 1,177.50 cm³ * 2/3
= 2355 cm³ ÷ 3
= 785 cm³
Volume of the cone = π r² h/3
a) 3.14 * 15² * 5/3 = 1177.50 cm³
b) 3.14 * 10² * 7.5/3 = 785 cm³
c) 3.14 * 7.5² * 10/3 = 588.75 cm³
d) 3.14 * 5² * 15/3 = 392.50 cm³
Just take <span>7.8×10^5 divided by 24
you will get 32500
32500 = 3.250 x 10^4
answer
</span><span>3.250×10^4 days</span>
we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>
We know that at 8:00 a.m. there were t inches of snow in the ground.
At 5:00 p.m. there were 3t inches of snow in the ground.
Then the difference between the heights of the snow is:
3t- t = 2t
And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:
3t = 12in
t = (12in)/3 = 4 in
Replacing that in the difference of heights:
2t = 2*4in = 8in
From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
