Answer:
The king left his castle with 44 silver coins.
Step-by-step explanation:
A king left his castle with a bag of silver coins and he gave his coins to 3 peasants in an order. Finally he went home with two coins left.
To solve this question we calculate it in reverse order.
Finally the king has in his bag = 2 coins
Before it he met third peasant king had =
= (2+2) × 2
= 4×2 = 8
Before the king met third peasant, he had 8 coins.
Before he met Second peasant king had :
= (8+2) × 2
= 10 × 2 = 20
Before he met second peasant king had 20 coins.
Before he met first peasant he had :
= (20+ 2) × 2
= 22 × 2 = 44
Before King met first peasant he had 44 silver coins.
