The metric system is used all around the world because it goes off a ten number base and is easy to calculate.
qualitative data is in words
quantitative data is in numbers
Answer:
5.99 moles of
Explanation:
In this case, we can start with the <u>decomposition</u> of , so:
<u>(Reaction 1)</u>
The can react with carbon to produce :
<u>(Reaction 2)</u>
If we 8.99 mol of , we can calculate the moles of that we need. In reaction 2 we have a <u>molar ratio</u> of 1:2 (2 moles of will produce 1 mol of ):
With this value and using the <u>molar ratio</u> in reaction 1 (3 moles of are producing by each mol of ), so:
So, we will need 5.99 moles of to produce 8.99 mol of .
I hope it helps!
Answer:
Approximately 4574.86 years
Explanation:
Hello,
To find the age of this sample, we should first of all convert the disintegration per minute to per year so that we can work on the same unit as our half life (T½), then we can find the disintegration constant and use it to find the year of the artifact.
Data;
T½ = 5730 years
Initial rate of radioactivity (No) = 15.3 disintegration per minute.
Current rate of radioactivity (N) = 8.8 disintegration per minute.
1 year = 525600 minutes
1 mins = 8.8 disintegration
525600mins = N disintegration
N = (525600 × 8.8) / 1
N = 4625280
1 mins = 15.3 disintegration
525600 mins = No
No = 8041680
But T½ = In2 / λ
λ = In2 / T½
λ = 0.693 / 5730
λ = 1.209×10⁻⁴ (this is the disintegration constant)
We can now find the how old the artifact is using our disintegration constant and other parameters.
In(N÷No) = -λt
In[4625280 / 8041680] = -(1.209×10⁻⁴ × t)
In[0.57516] = -1.209×10⁻⁴t
-0.5531 = -1.209×10⁻⁴ t
Solve for t
t = 0.5531 / 1.209×10⁻⁴
t = 4574.86 years
The artifact is approximately 4574.86 years
C) Argon
It has full outer shell