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9966 [12]
3 years ago
7

If 2.45 g of iron are placed in 1,5 L of 0.25M HCl, how many grams of FeCl2 are obtained? Identify the limiting and excess react

ants in this single replacement reaction. Fe + 2HCl = FeCl2 + H2
Chemistry
1 answer:
jekas [21]3 years ago
5 0

Answer:

5.56g of FeCl2 can be produced

Explanation:

To solve this question we must find the moles of each reactant. With the moles and the chemical equation we can find limiting reactant. With limiting reactant we can find the moles of FeCl2 and its mass as follows:

<em>Moles HCl:</em>

1.5L * (0.25mol / L) = 0.375 moles HCl

<em>Moles Fe -Molar mass: 55.845g/mol-</em>

2.45g * (1mol / 55.845g) = 0.0439 moles Fe

For a complete reaction of 0.375 moles HCl are needed:

0.375 moles HCl * (1mol Fe / 2mol HCl) = 0.1875 moles Fe

As there are just 0.0439 moles Fe, <em>Fe is limiting reactant</em>

<em />

1mol of Fe produce 1 mole of FeCl2, 0.0439 moles Fe produce 0.0439 moles of FeCl2. The mass is:

<em>Mass FeCl2 -Molar mass: 126.751g/mol:</em>

0.0439 moles Fe * (126.751g / mol) =

<h3>5.56g of FeCl2 can be produced</h3>
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Answer:

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Explanation:

Alanine, a 3-carbon amino acid reacts with α-ketoglutarate, a 5-carbon ketoacid, to produce pyruvate, a 3-carbon compound which is one of the glycolytic products in aerobic respiration, and glutamate, a 5-carbon amino acid, with the aid of alanine transaminase (ALT). The amino group from alanine is transfered from the α-carbon of alanine to the α-carbon of the α-ketoglutarate.

Aspartate, a 4-carbon amino acid also reacts with α-ketoglutarate to form oxaloacetate, a 4-carbon ketoacid which is present as an intermediate in the citric acid cycle, and glutamate. The amino group transfer occurs between the α-carbon of aspartate and the α-carbon of α-ketoglutarate.

Unlike the presence of a ketoacid in the conversion of alanine and aspartate to their corresponding amino acids, glutamate conversion to α-ketoglutarate, an intermediate in the citric acid cycle, involves no ketoacids as an amino group acceptor from glutamate. The amino group is freely released as an ammonium ion. The reaction involves the presence of a cofactor, NAD+ or NADP+, water (H2O) and glutamate dehygrogenase (GDH).

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7 0
3 years ago
What is the mass of 4.38 x 10^24 formula units of sodium chloride (NaCl)?
lana66690 [7]

Answer:

Mass = 427.05 g

Explanation:

Given data:

Formula units of sodium chloride = 4.38 ×10²⁴

Mass of NaCl = ?

Solution:

One mole contain formula units = 6.022 ×10²³

4.38×10²⁴ formula units × 1mol /6.022 ×10²³ formula units

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How many moles of FeCr2O7 are required to produce 20 moles of CO2​
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