Answer:
The answers are options A, D and E
Explanation:
Shut circuit implies a total electrical association around which flow streams or courses. When you have a progression of electrical wires interfacing with one another and finishing a circuit so flow goes from one end of the hover to alternate, this is a case of a shut circuit. A broken wire or an "open" (off) switch both leave holes in a circuit keeping electrons from going from one side of the power source to the next. In this way, electrons won't stream. This circumstance is called an open circuit. A shut (on) switch implies that the circuit through the switch is connected.The meaning of an open circuit is a broken way for an electrical flow because of an open switch or frayed wire. A case of an open circuit is a string of electric lights that don't work on the off chance that one globule goes out. YourDictionary definition and utilization precedent. Shut circuit implies an entire electrical association around which flow streams or circles. When you have a progression of electrical wires associating with one another and finishing a circuit so flow goes from one end of the hover to alternate, this is a case of a shut circuit.
Answer:
The strong acid reacts with the weak base in the buffer to form a weak acid, which produces few H+ ions in solution and therefore only a little change in pH.
Explanation:
When a strong acid is added to the buffer, the acid dissociates and furnish hydrogen ions which combine with the conjugate of the weak acid, forming weak acid. The weak acid dissociates to only some extent and can furnish only some protons and there is no significant change in the pH.
Hence, option B is correct.
Answer:
You start with 9.4 x 1025 molecules of H2.
You know that an Avogadro's number of molecules of H2 has a mass of 2.0 g.
To solve, 9.4 x 1025 molecules H2 x (2.0 g H2 / 6.023 x 1023 molecules H2) = 312. g H2
Explanation:
Answer: The standard enthalpy of formation of this isomer of 
is -210.9 kJ
Explanation:
The given balanced chemical reaction is,
First we have to calculate the enthalpy of formation of 
.
![\Delta H^o=[n_{CO_2}\times \Delta H_f^0_{(CO_2)}+n_{H_2O}\times \Delta H_f^0_{(H_2O)}]-[n_{O_2}\times \Delta H_f^0_{(O_2)+n_{C_8H_{18}}\times \Delta H_f^0_{(C_8H_{18})}]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo%3D%5Bn_%7BCO_2%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28CO_2%29%7D%2Bn_%7BH_2O%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28H_2O%29%7D%5D-%5Bn_%7BO_2%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28O_2%29%2Bn_%7BC_8H_%7B18%7D%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28C_8H_%7B18%7D%29%7D%5D)
where,
We are given:
Putting values in above equation, we get:
![-511.3kJ/mol=[(8\times -393.5)+(9\times -241.8)]-[(\frac{25}{2}\times 0)+(1\times \Delta H_f^0_{(C_8H_{18})}](https://tex.z-dn.net/?f=-511.3kJ%2Fmol%3D%5B%288%5Ctimes%20-393.5%29%2B%289%5Ctimes%20-241.8%29%5D-%5B%28%5Cfrac%7B25%7D%7B2%7D%5Ctimes%200%29%2B%281%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28C_8H_%7B18%7D%29%7D)
Answer:
True
Explanation:
Limiting reactant - the reactant which get completely consumed in a chemical reaction , is known as the limiting reactant .
As, the concentration of limiting reactant after the completion of the reaction will be zero , hence, it is used to determine the concentration of other reactants .
For example,
for a general reaction -
A + B ---> 3C
Assuming B to be the limiting reactant ,
hence, the concentration of C and A can be determined as -
1 mol of B can give 3 mol of C and 1 mol of A is used for the reaction.
