Answer:
Attached is the graph
Step-by-step explanation:
We know that both triangles are congruent because of the HL Theorem (in which both the hypotenuse and a leg are confirmed as congruent in a right triangle). Because of this, we know 4x = 6x - 58
Subtract 6x from both sides:
-2x = -58
Multiply both sides by -1:
2x = 58
Divide both sides by 2:
x = 29
The answer is Option C, x = 29
Answer:
47/100
Step-by-step explanation:
47 -> 0.47 47/100 = 0.47
Answer:
Answer: 17892
Solution:
The multiples of 7 between 0 to 500 are:
7x1 = 7
7x2 = 14
7x3 = 21
7x4 = 28
7x5 = 35
………….
7x70 = 490
7x71 = 497
Therefore total number of multiples of 7 between 0 and 500 are 71. If we denote by S71 the sum of all these multiples,
S71 = 7+14+21+28+35+…………+490+497
= 7(1+2+3+4+………………….+70+71)
The series within parentheses is the sum of the first 71 natural numbers and the sum is given by the formula n(n+1)/2, where n=total number of terms=71 . Substituting for n,
S71 = (7x71x72)/2 = 7x71x36 = 17892 (Answer
Step-by-step explanation: