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3 years ago

Find the x-coordinate of the vertex of a parabola if the x-intercepts are (3,0) and (-9,0)

Mathematics

1 answer:

madam [21]3 years ago

8 0

Answer:

x = -3

Step-by-step explanation:

The vertex lies on the axis of symmetry, whose x-coordinate is halfway between -9 and 3: x = -3

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Can someone help.....

tatyana61 [14]

Answer:

Step-by-step explanation:

formula for circumference of a circle is $\pi$ d

7 $\pi$ = $\pi$ d

d = 7

5 0

3 years ago

If the base of the parallelogram is 8 and the perimeter is 28 then what is the area?

LUCKY_DIMON [66]

Answer:

the answer is 28 for the area.

7 0

2 years ago

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

3 years ago

The director of a museum recorded the number of students and adult chaperones in several school groups visiting the museum. She

sasho [114]

Answer:

b. 119

Step-by-step explanation:

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2 years ago

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s2008m [1.1K]

Answer:

11 yards

Step-by-step explanation:

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2 years ago

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