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Setler [38]
2 years ago
5

I need help problem in the picture below

Mathematics
1 answer:
Firlakuza [10]2 years ago
5 0

Answer:

The answer is three

Step-by-step explanation:

The formula to find the area is the width times the length. The area of the big rectangle is three times more than the smaller rectangle.

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Can u guys PLEASE answer this question ASAP. THIS IS EXTREMELY URGENT
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Answer:

14.55 hope this help

Step-by-step explanation:

3 0
3 years ago
Solve the equation:<br> 12=19-√3x-11
Alekssandra [29.7K]
The answer is x=20. You isolate the square root. Eliminate the radical on the left handside. And then solve it!
4 0
3 years ago
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The owner of a small pet supply store wants to open a second store in another city, but he only wants to do so if more than one-
Andrei [34K]

Answer:

The answer is "The null hypothesis was rejected".

Step-by-step explanation:

Following are the right-tailed test:

Calculating the null and alternative hypothesis:

H_0 : p = 0.3333\\\\H_a : p > 0.3333\\\\n = 150\\\\x = 64\\\\\hat{p} = \frac{x}{n} = \frac{64}{150} = 0.4267\\\\P_0 = 0.3333\\\\1 - P_0 = 1 - 0.3333 = 0.6667\\\\

z = \frac{\hat{p} - P_0}{[\sqrt{\frac{P_0 \times (1 - P_0 )}{n}}]}

   = \frac{0.4267 - 0.3333}{[\sqrt{\frac{(0.3333 \times 0.6667)}{150}}]}\\\\= 2.426

Calculating the right-tailed test:

P(z > 2.426) = 1 - P(z < 2.426) = 1 - 0.9924 = 0.0076\\\\P-value = 0.0076\\\\\alpha = 0.05\\\\P-value < \alpha

Therefore, we reject the null hypothesis.

This example shows that more than a third of the families own pets in this town.

5 0
3 years ago
Dinosaur fossils are often dated by using an element other than carbon, like potassium-40, that has a longer half life (in this
Firlakuza [10]
The amount of substance left of a radioactive element of half life, t_{\frac{1}{2}} after a time, t, is given by:

N(t)=N_0\left( \frac{1}{2} \right)^ \frac{t}{t_{  \frac{1}{2} }}

Given that <span>potassium-40 has a half life of approximately 1.25 billion years.

The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

0.1=100\left( \frac{1}{2} \right)^ \frac{t}{1.25}} \\  \\ \Rightarrow\left( \frac{1}{2} \right)^ \frac{t}{1.25}}=0.001 \\  \\ \Rightarrow\frac{t}{1.25}\ln\left( \frac{1}{2} \right)=\ln(0.001) \\  \\ \Rightarrow \frac{t}{1.25}= \frac{\ln(0.001)}{\ln\left( \frac{1}{2} \right)} =9.966 \\  \\ t=9.966(1.25)=12.5

Therefore, </span><span>the maximum age of a fossil that we could date using 40k is 12.5 billion years.</span>
3 0
3 years ago
Write each fraction as the sum of a whole number and a fraction less than 1
Tpy6a [65]

Given:

The fractions are:

\dfrac{6}{5},\dfrac{11}{7},\dfrac{21}{4}

To find:

The each fraction as the sum of a whole number and a fraction less than 1.

Solution:

The given fraction is \dfrac{6}{5}.

\dfrac{6}{5}=\dfrac{5+1}{5}

\dfrac{6}{5}=\dfrac{5}{5}+\dfrac{1}{5}

\dfrac{6}{5}=1+\dfrac{1}{5}

Therefore, the given fraction \dfrac{6}{5} can be written as 1+\dfrac{1}{5}.

The given fraction is \dfrac{11}{7}.

\dfrac{11}{7}=\dfrac{7+4}{7}

\dfrac{11}{7}=\dfrac{7}{7}+\dfrac{4}{7}

\dfrac{11}{7}=1+\dfrac{4}{7}

Therefore, the given fraction \dfrac{11}{7} can be written as 1+\dfrac{4}{7}.

The given fraction is \dfrac{21}{4}.

\dfrac{21}{4}=\dfrac{20+1}{4}

\dfrac{21}{4}=\dfrac{20}{4}+\dfrac{1}{4}

\dfrac{21}{4}=5+\dfrac{1}{4}

Therefore, the given fraction \dfrac{21}{4} can be written as 5+\dfrac{1}{4}.

7 0
3 years ago
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