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Svetradugi [14.3K]
3 years ago
13

Answer soon plz

Mathematics
1 answer:
shusha [124]3 years ago
7 0

Answer:

A) 25 < (1/2)x + 4

B)The X=42                              that is all i got on this one :l i hope it helps a bit

Step-by-step explanation:

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M - 1 = 2 what do I need to do to solve.
andreyandreev [35.5K]

In order to solve this, start by adding 1 to both sides of the equation.


m-1=2

+1 +1

-----------

m=3


The solution to your equation is 3.


You can also check to see if this is true by replacing m with 3.

m-1=2

3-1=2

7 0
3 years ago
You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte
Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \,  otherwise }} \right.

a)  We calculate  the probability that you need less than 5 minutes to get up:

P(x

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate  the probability that you will need between 8 and 13 minutes:

P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3

Therefore, the probability is P(8<x<13)=0.3.

d)  We calculate the probability that you will be late to each of the 9:30am classes next week:

P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6

You have 9:30am classes three times a week.  So, we get:

P=0.6^3=0.216

Therefore, the probability is P=0.216.

e)  We calculate the probability that you are late to at least one 9am class next week:

P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1

Therefore, the probability is P=1.

3 0
3 years ago
X+y=4 and x-y=6 substitution
vlabodo [156]
Y = -1
x = 5
jeng jeng jeng
4 0
3 years ago
Read 2 more answers
An archer has a mean distance of 1.6 inches and a MAD distance of 1.3 inches in the first round. In the second round, the archer
schepotkina [342]
I think it’s 1.5 cause it shows it
7 0
3 years ago
Sold the equation. Round to the nearest hundredth. <br><br>17 · <img src="https://tex.z-dn.net/?f=1.8%5E%7B-x%2B7%7D%20%3D%205"
svetlana [45]

Answer:

Final answer is approx x=4.26.

Step-by-step explanation:

Given equation is 1.8^{-x+7} = 5

Now we need to solve equation 1.8^{-x+7} = 5 and round to the nearest hundredth.

1.8^{-x+7} = 5

\log(1.8^{-x+7}) = \log(5)

(-x+7)\log(1.8) = \log(5)

(-x+7) = \frac{\log(5)}{\log(1.8)}

(-x+7) = \frac{0.698970004336}{0.255272505103}

-x+7 = 2.73813274192

-x = 2.73813274192-7

-x =−4.26186725808

x =4.26186725808

Round to the nearest hundredth.

Hence final answer is approx x=4.26.

4 0
3 years ago
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