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Alex
1 year ago
14

the area of a parallelogram measures 171 cm the base of the parallelogram is 18 cm in length which of the following best represe

nts the height of the parallelogram A. 11cm B. 9.5 C. 13.5 D. 8cm give step by step explanation ​
Mathematics
1 answer:
goblinko [34]1 year ago
3 0

Answer:

A=bxh

171 cm=18cmxh

h=171/18

= 9.5 cm

which is B no.

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If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)
Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

\log_dabc=\log_da+\log_db+\log_dc

Then using the change of base formula, we can derive the relationship

\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}

This immediately tells us that

\log_dc=\dfrac1{\log_cd}=\dfrac12

Notice that none of a,b,c,d can be equal to 1. This is because

\log_1x=y\implies1^{\log_1x}=1^y\implies x=1

for any choice of y. This means we can safely do the following without worrying about division by 0.

\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}

so that

\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23

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\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34

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###

Another way to do this:

\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}

\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}

\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12

Then

abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}

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\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}

4 0
2 years ago
Can you help me on 16, 17, 18, 19, and 20
snow_tiger [21]

Answer:

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hope this helps

3 0
2 years ago
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JulsSmile [24]

Answer:

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In this problem we have:

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d_2=1.3 mi is the distance travelled during the 2nd day

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So, the  distance travelled on the 7th day is 19.9 miles.

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2 years ago
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