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enyata [817]
3 years ago
5

Luis forma una torre con seis dados normales colocados sobre una mesa, tal como se muestra en la figura. Considerando que él pue

de moverse alrededor de la mesa, ¿Cuántos puntos cómo mínimo son visibles para él?
Mathematics
1 answer:
vodka [1.7K]3 years ago
3 0

El número de puntos visibles para el será de 84.

<h3><u>Sumas</u></h3>

Dado que Luis forma una torre con seis dados normales colocados sobre una mesa, para determinar cuántos puntos cómo mínimo son visibles para él se debe realizar el siguiente cálculo:

La suma de la cara del dado ubicada boca abajo, más su contraria, siempre dará 7. Por ende, en tanto 1 + 2 + 3 + 4 + 5 + 6 - 7 = 14, y 14 x 6 es igual a 84, el número de puntos visibles para el será de 84.

Aprende más sobre sumas en brainly.com/question/16620242

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Your office manager used 45 paperclips for handouts at his presentation from the 450 paperclips available in the stock room. Wha
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It would be 90%..... 45/450= 10%.... so there would be 90% not being used.
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3 years ago
PLSS ANSWER MY QUESTION
Taya2010 [7]

Answer:

1) Area of frame: 140cm^2 ; Area of picture: 40cm^2 ; Total Area: 180cm^2.      

2) Area 1 =  48cm^2 ; Area 2 = 12cm^2 ; total area = 60cm^2 [first answer line : 60cm^2]

Step-by-step explanation:

1. So to answer this question, you have to find the inner photo area first (which you will then subtract from the overall rectangle area to get the photo frame area).

To find area, you multiply length x width. For this question, there are not enough measurements given to initially multiply length and width. So, assuming that the photo is centered on the frame and the frame width is consistent along all sides, you find the difference between the overall length (12) and the picture length (5).

12 - 5 = 7

The leftover area (outside of the picture) is 7 cm (half of seven on both sides), so one side can be assumed to be : 3.5 cm

this means that 15 cm - 3.5 cm of both sides lengths (difference between the two lengths given) is the height of the photo, 15 - 3.5(2) = 8

So, the dimensions/measurements of the photo are 5 cm by 8 cm.

This means that the inner photo area is 40 (5 x 8) cm

The area of the frame will be the area of the total rectangle [12 x 15] - the inner photo area [40].  [ (12)(15) - 40 ]

[180 - 40] = 140 cm

(area is measured in squared units, so the area of the frame should be written as 140cm^{2} ; and the area of the photo should be written as 40cm^{2})

The total area is the entire area of the rectangle: (12)(15) = 180. (This should be written as 180cm^2)

--------------------------------------

2) Finding the area of a shape that isn't a simple rectangle is easier if you separate the shape into smaller rectangles. I will separate the two rectangles into 4 x 12 and 2 x 6 [6 cm would be the remaining side length if you remove the length of 4].

{you can separate the shape in multiple ways, so my answer is only one answer to this problem out of other splits.}

as mentioned, the area is length x width.

4 x 12 = 48.

2 x 6 = 12. Once again, you should write area in squared units.

(the area 1 should be written as 48cm^{2} ; the area 2 should be written as 12cm^2)

you can combine the separated areas (add them) to find the total area. 48 + 12 = 60.

(the total area should be written in squared units also, so the total area should be written as: 60cm^2)

The area of the figure is 60cm^2

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