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3 years ago

Can someone help with this?

Mathematics

2 answers:

MAXImum [283]3 years ago

8 0

I belive it is the second option!

gayaneshka [121]3 years ago

3 0

8(2y+y)

hope it helps!!!

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Giving brainlest and 20 points

Natali5045456 [20]

Answer:

C. 40 square inches but i could be wrong

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3 years ago

Complete each statement with a number that makes the statement true.

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

1). (d). 5°C < 7°C

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3). (c). 4°C > - 4°C

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7 0

3 years ago

Rewrite the expression using GCF and distributive property. 64x-24

Ede4ka [16]

The greatest common factor between 64 and 24 is 8

Let's divide both terms in the expression by 8 and leave the expression in parenthesis...

Like this!

64x -24

$\frac{64x}{8} - \frac{24}{8}$

8x - 3

Leave 8 we divided outside the parenthesis

Now we have this!

8( 8x - 3)

This is the distributive property form!

4 0

2 years ago

Read 2 more answers

Please help ASAP If f(x) = x^2-6x+2 and g(x) =sqrt x find a.) (fog) (x) b.) (gof) (-2)

Rudik [331]

$\large\begin{array}{l} \left\{\!\begin{array}{l} \mathsf{f(x)=x^2-6x+2}\\ \mathsf{g(x)=\sqrt{x}}\\ \end{array}\right. \end{array}$

$\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}$

______

$\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}$

______

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$\large\textsf{I hope this helps. :-)}$

Tags: composite function composition evaluate algebra

7 0

3 years ago

What is 1/10 - 13/14

kolbaska11 [484]

Answer:

0.828

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3 years ago

Read 2 more answers