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Liula [17]
3 years ago
10

Find the length of the second base of a trapezoid with one base measuring 12 ft, a height of 4 ft, and an area of 58 square ft.

Mathematics
1 answer:
aleksandrvk [35]3 years ago
3 0
The second base would be 17 feet.
To find the area of a trapezoid it is (base1 + base2) height
__________________
2
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8. Solve the following triangle for all missing sides and angles.
vova2212 [387]

Answer:

Parte1 :

∡B= 180 - (42 + 83)= 55°

Parte2 :

Using the law of sines : \frac{sin 42}{a} = \frac{sin 55}{175} ⇔ a = sin42 \frac{175}{sin 55} ⇔ a= 142.95

Parte3 :

Using the same law : c = sin 83\frac{a}{sin 42}  or  c= sin 83\frac{175}{sin 55}  ⇔ c= 212.04

7 0
2 years ago
Multi step equations <br> 4-5x=29
Gemiola [76]

Answer: x = -5

Step-by-step explanation:

1) subtract 4 from both sides (-5x = 25)

2) divide -5 from both sides (x = -5)

Then you have the answer!

6 0
3 years ago
The angles of a pentagon are x, x − 5 0 , x + 100 , 2x + 150and 2x + 300 . Find all the angles.
miv72 [106K]

Answer:

The interior angles are 70°,65°,80°,155° and 170°

Step-by-step explanation:

step 1

Find the sum of the interior angles of the pentagon

The sum is equal to

S=(n-2)*180°

where

n is the number of sides of polygon

n=5 (pentagon)

substitute

S=(5-2)*180°=540°

step 2

Find the value of x

Sum the given angles and equate to 540

x+(x-5)+(x+10)+(2x+15)+(2x+30)=540°

7x+50=540°

7x=490°

x=70°

step 3

Find all the angles

x=70°

(x-5)=(70-5)=65°

(x+10)=(70+10)=80°

(2x+15)=(2*70+15)=155°

(2x+30)=(2*70+30)=170°

8 0
2 years ago
Simplify the expression -3 devided by -2/5. A. -7 1/2 B. -1 1/5 C. 1 1/5 D. 7 1/2
Llana [10]

Answer:

D. 7 1/2

Step-by-step explanation:

-3 divided by -2/5

-(-3(-5/2)

-(-3 x 5/2)

-15/2

7 1/2

Hope it helps

7 0
3 years ago
Factor each completely<br><br> n^2 - 11n + 10
Charra [1.4K]

{n}^{2}  - 11n + 10 =

(n - 1)(n - 10)

.................................................

3 0
2 years ago
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