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4 years ago

PLEASE HELP ILL GIVE MEDALS AND MARK BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!! NEEDS TO BE ALEGABRA 2 MEATHOD!!!!!!!!

1 answer:

8 0

Simplify \frac{5}{3}x35x to \frac{5x}{3}35x

x-\frac{5x}{3}<3x−35x<3

2

Simplify x-\frac{5x}{3}x−35x to -\frac{2x}{3}−32x

-\frac{2x}{3}<3−32x<3

3

Multiply both sides by 33

-2x<3\times 3−2x<3×3

4

Simplify 3\times 33×3 to 99

-2x<9−2x<9

5

Divide both sides by -2−2

x>-\frac{9}{2}x>−29

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Step-by-step explanation:

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The equation 3sinx+cos^2x=2 is solved below Please help! Thanks!

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We have that
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the difference between the squares of two numbers is 3. Twice the square of the first number increased by the square of the seco

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Answer:

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Step-by-step explanation:

Given as :

The difference between the squares of two number = 3

And , Twice the square of the first number increased by the square of the second number is 9

Now, Let The first number = F

And The second number = S

So , According to question

F² - S² = 3 .......A

2 F² - S² = 9 ........B

Now, solving the equations

( 2 F² - S² ) - ( F² - S² ) = 9 - 3

Or, ( 2 F² - F² ) + ( S² - S² ) = 6

Or, F² + 0 = 6

∴ F = $\sqrt{6}$

Putting the value of F in eq A

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Or, 6 - 3 = S²

Or, S² = 3

∴ S = $\sqrt{3}$

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