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3 years ago

Jeff drinks 2/3 of a glass of juice write A fraction that is equivalent to 2/3

Mathematics

1 answer:

Whitepunk [10]3 years ago

4 0

Answer:

4/6 , 8/12, etc

Step-by-step explanation:

A fraction that can be equivalent to 2/3 is 4/6 or 8/12

This is because if you were to multiply 2/3 by 2/2 you multiplied by the same amount and also the product of that can be simplified to 2/3s.

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What is the slope of the line segment?<br><br> 5<br> 1/5<br> -1/5<br> -5

Elanso [62]

Answer:

Step-by-step explanation:

Calculate slope by choosing two points. (1, 5) and (2, 10)

slope = (10 - 5) / (2 - 1) = 5/1 = 5

6 0

4 years ago

In circle E with m DEF 36 and DE = 3 units find area of

deff fn [24]

Answer:

A ≈ 2.83 units²

Step-by-step explanation:

The area (A) of the sector is calculated as

A = area of circle × fraction of circle

= πr² × $\frac{36}{360}$

= π × 3² × $\frac{1}{10}$

= $\frac{9\pi }{10}$

≈ 2.83 units² ( to the nearest hundredth )

4 0

3 years ago

The slope of the line that passes through the points (-2, -3) and (8, -3) is....

andre [41]

Answer:

Step-by-step explanation:

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-2,\:-3\right),\:\\\left(x_2,\:y_2\right)=\left(8,\:-3\right)\\\\m=\frac{-3-\left(-3\right)}{8-\left(-2\right)}\\\\m=0$

8 0

3 years ago

Read 2 more answers

Find the tangent plane to the given surface of f(x,y)=6- 6/5 x-y at the point (5, -1, 1). Make sure tat your final answer for th

HACTEHA [7]

Answer:

Required equation of tangent plane is $z=\frac{6}{5}(x-5y-11)$ .

Step-by-step explanation:

Given surface function is,

$f(x,y)=6-\frac{6}{5}(x-y)$

To find tangent plane at the point (5,-1,1).

We know equation of tangent plane at the point $(x_0,y_0,z_0)[/tex] is,

$z=f(x_0,y_0)+f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)\hfill (1)$

So that,

$f(x_0,y_0)=6-\frac{6}{5}(5+1)=-\frac{6}{5}$

$f_x=-\frac{6}{5}y\implies f_x(5,-1,1)=\frac{6}{5}$

$f_y=-\frac{6}{5}x\implies f_y(5,-1,1)=-6$

Substitute all these values in (1) we get,

$z=\frac{6}{5}(x-5)-6(y+1)-\frac{6}{5}$

$\therefore z=\frac{6}{5}(x-5y-11)$

Which is the required euation of tangent plane.

4 0

3 years ago

In the figure, line segment VR is parallel to line segment US and m<1 = 45 degrees what is m<4?

Jobisdone [24]

The measure of ∠4 is 45°.

Solution:

Line segment VR is parallel to the line segment US.

m∠1 = 45°

∠1 and ∠4 are corresponding angles.

<em>If two lines are parallel, then the corresponding angles are congruent.</em>

m∠1 = m∠4

45° = m∠4

m∠4 = 45°

The measure of ∠4 is 45°.

3 0

4 years ago