Which classification best represents a triangle with side lengths 10 in., 12 in., and 15 in.?

Find the missing coordinate to complete the ordered-pair solution to the given linear equation: A) y+6x=5 (a) (-1,?)

N76 [4]

A
a) y+6x=5 if x= -1 then y+6(-1)=5 then y = 11
b) same thing if x = 3 then y+6(3)=5 y+18=5 subtract both sides by -18 and leave y on left then add 5+(-18)= 13 then y=13

B same as above
question (a) asks you to solve for y because x is -2
(b) asks you to solve for x because y is known
3x+2y=-6 if y = 3 you write 3x+2(3)=-6 3x+6=-6 move the +6 over to right side by subtracting 6 from both side 3x=-6 + -6 so 3x=-12 to get rid of the 3 and only leave the x you want to divide both side by 3 then x= -12/3 then the answer would be x=-4

4 0

3 years ago

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An electronics retailer receives a shipment of 6,000CDs to distribute to its stores. A quality control manager inspects a random

Alex17521 [72]

Answer: 300

Step-by-step explanation:

Given , An electronics retailer receives a shipment of 6,000CDs to distribute to its stores.

i.e, Total CD's he has now = 6,000

Also, a quality control manager inspects a random sample(S) of 40CD's , the number of defective(D) CD's are 2.

Then , the proportion of defective( D) CD's = $\dfrac{D}{S}=\dfrac{2}{40}=0.05$

Now , the number of CDs in the shipment are likely to be defective = ( Total CD's) x (proportion of defective CD's)

= 6000 x 0.05

=300

Hence, the number of CDs in the shipment are likely to be defective =300

8 0

3 years ago

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Question 3 (1 point) Find the value of x for the right triangle. 15 30° Х

Marina86 [1]

Answer:

x = 8.7

Step-by-step explanation:

Reference angle = 30°

Opposite side length = x

Adjacent side length = 15

Apply trigonometric function, TOA:

Tan 30° = Opp/Adj

Plug in the values

Tan 30° = x/15

Multiply both sides by 15

15*Tan 30° = x

8.66025404 = x

x = 8.7 (nearest tenth)

6 0

3 years ago

Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)

strojnjashka [21]

we know that

If the vertex is on the y-axis, then the x-coordinate of the vertex is equal to zero

we are going to verify the vertex of each one of the functions to determine the solution

Remember that

The equation in vertex form of a vertical parabola is equal to

$y=a(x-h)^{2} +k$

where

(h,k) is the vertex

if $a>0$ -------> the parabola open upward (vertex is a minimum)

if $a$ -------> the parabola open downward (vertex is a maximun)

case A) $f(x)=(x-2)^{2}$

This is a vertical parabola open upward

the vertex is the point $(2,0)$

therefore

The function $f(x)=(x-2)^{2}$ does not have a vertex on the y-axis

case B) $f(x)=x(x+2)$

$f(x)=x(x+2)=x^{2}+2x$

convert to vertex form

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)+1=x^{2}+2x+1$

Rewrite as perfect squares

$f(x)+1=(x+1)^{2}$

$f(x)=(x+1)^{2}-1$

the vertex is the point $(-1,-1)$

therefore

The function $f(x)=x(x+2)$ does not have a vertex on the y-axis

case C) $f(x)=(x-2)(x+2)$

$f(x)=(x-2)(x+2)=x^{2}-2^{2}$

$f(x)=x^{2}-4$

the vertex is the point $(0,-4)$

The x-coordinate of the vertex is equal to zero

therefore

The function $f(x)=(x-2)(x+2)$ has a vertex on the y-axis

case D) $f(x)=(x+1)(x-2)$

$f(x)=(x+1)(x-2)\\ \\f(x)= x^{2}-2x+x-2 \\ \\f(x)= x^{2} -x-2$

convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+2= x^{2} -x$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)+2+0.25= x^{2} -x+0.25$

$f(x)+2.25= x^{2} -x+0.25$

Rewrite as perfect squares

$f(x)+2.25= (x-0.50)^{2}$

$f(x)=(x-0.50)^{2}-2.25$

the vertex is the point $(0.5,-2.25)$

therefore

The function $f(x)=(x+1)(x-2)$ does not have a vertex on the y-axis

the answer is

$f(x)=(x-2)(x+2)$

6 0

3 years ago

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X²+x=0 x³-25x=0 x²=4x 4x²-4x=1

-BARSIC- [3]

Answer:

x²+ x = 0

x ( x +1 ) = 0

x = -1

x³-25x=0

x ( x² - 25 ) = 0

x² = 25

x = 5

x²=4x

x² - 4x = 0

x ( x- 4 ) = 0

x = 4

4x²-4x=1

4x²-4x - 1 = 0

4 x² - 2x - 2x - 1 = 0

2x ( 2x - 1 ) - 1 ( 2x- 1 ) = 0

2x- 1 ) ² = 0

2x = 1

x = 1/ 2

mark me as brainliest

7 0

3 years ago