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andrew-mc [135]
3 years ago
11

The equation shows the reaction between zinc metal and hydrochloric acid.

Chemistry
2 answers:
liq [111]3 years ago
8 0
The balanced chemical reaction is written as:

<span>Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(g)
</span>
We are given the amount of the reactant zinc to be used in the reaction This amount would be the starting point for the calculation. It is as follows:

5.00 mol Zn ( 1 mol H2 / 1 mol Zn ) (2.02 g H2 / 1 mol H2 ) = 10.1 g H2

Therefore, the correct answer is the second option.
timurjin [86]3 years ago
7 0

Answer:

B. 10.1g

Explanation:

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2 years ago
Calculate the pH of a solution prepared by mixing: (Show your work for these calculations) pk of acetic acid is 4.75 a. two mole
kupik [55]

Answer:

Explanation:

To calculate pH you need to use Henderson-Hasselbalch formula:

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

Where HA is the acid concentration and A⁻ is the conjugate base concentration.

The equilibrium of acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka: 4,75

Where <em>CH₃COOH </em>is the acid and <em>CH₃COO⁻ </em>is the conjugate base.

Thus, Henderson-Hasselbalch formula for acetic acid equilibrium is:

pH = 4,75 + log₁₀ \frac{[CH_{3}COO^-]}{[CH_{3}COOH]}

a) The pH is:

pH = 4,75 + log₁₀ \frac{[2 mol]}{[2 mol]}

<em>pH = 4,75</em>

<em></em>

b) The pH is:

pH = 4,75 + log₁₀ \frac{[2 mol]}{[1mol]}

<em>pH = 5,05</em>

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7 0
3 years ago
The expected value for a chemical equation is 47g of water, after an experiment you find that you have 2.58 moles of water. What
strojnjashka [21]
<h3><u>Answer</u>;</h3>

Actual yield = 46.44 g

<h3><u>Explanation;</u></h3>

1 mole of water = 18 g/mol

Therefore;

The experimental yield = 2.58 moles

equivalent to ; 2.58 × 18 = 46.44 g

The theoretical value is 47 g

Percentage yield = 46.44/47 × 100%

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The questions asks for actual yield = 46.44 g

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Answer:

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2 years ago
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PLEASE ANSWER ASAP (WILL GIVE BRAINLIEST)
Flauer [41]

Answer:

I think it is either A. or B.

Explanation:

(I think!)

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3 years ago
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