Answer:
0.667 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 250 mL
Initial concentration (C₁) = 12 M
Final concentration (C₂) = 4.5 M
Final volume (V₂) =?
The final volume of the solution can be obtained by using the dilution formula as illustrated below:
C₁V₁ = C₂V₂
12 × 250 = 4.5 × V₂
3000 = 4.5 × V₂
Divide both side by 4.5
V₂ = 3000 / 4.5
V₂ = 667 mL
Finally, we shall convert 667 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
667 mL = 667 mL × 1 L / 1000 mL
667 mL = 0.667 L
Thus, the volume of the solution prepared is 0.667 L
At the anode (A), chloride (Cl-) is oxidized to chlorine. ... At the cathode (C), water is diminished to hydroxide and hydrogen gas. The net procedure is the electrolysis of a fluid arrangement of NaCl into mechanically helpful items sodium hydroxide (NaOH) and chlorine gas.
The red sign pops up on the side of the bus.
Answer:
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Explanation:
Step 1: Data given
Mass of sodium bicarbonate = 2.7 grams
Step 2: The balanced equation
HCl + NaHCO3 ⇔ NaCl + H2O + CO2
Step 3: Calculate moles NaHCO3
moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles
Step 4: Calculate moles HCl
For 1 mol NaHCO3 we need 1 mol HCl
For 0.032 moles NaHCO3 = 0.032 moles HCl
Step 5: Calculate mass HCl
Mass HCl = moles HCl * molar mass HCl
mass HCl = 0.032 * 36.46 g/mol= 1.17 grams
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Answer:
The activation energy of an endothermic reaction
A) must be greater than the required △H
Explanation:
endothermic reaction : Are those which absorbs heat from the surrounding
.<em>This energy provide activation energy for the reaction to occur</em>.
So activation energy becomes more than enthalpy.
