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3 years ago

PLEASE HELP ME!

Chemistry

1 answer:

makkiz [27]3 years ago

4 0

Answer:

Explanation:

Q and R forms a nitrate. When dissolved in water it will form a solution with a pH greater than 7 because the solution is alkaline.

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What happens to the energy of gas particles when an elastic collision takes place?

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A gas sealed in a drum container occupies 7.70 L at a sizzling 325C degrees. What will the volume be if the drum is quickly chi

grigory [225]

The volume of the drum after chilled quickly is 3.6 L.

<u>Explanation:</u>

As per the Charles Law, for any gas at constant pressure, volume of the gas is in direct proportion with the temperature measured in Kelvin. As the temperature increases, the gas expands and vice versa.

$$\frac{V1}{T1} = \frac{V2}{T2} \\$

After chilling the drum, the volume will get reduced and it can be found as,

V2 = $$\frac{V1T2}{T1}$

= $$\frac{7.7 L \times 282 K}{598 K}$

= 3.6 L

Here the drum is chilled quickly, that is temperature is reduced and so the volume also decreases.

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3 years ago

Heat transfer putting a heating pad on leg

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4 years ago

When heated a sample consisting of only CaCO3 and MgCO3 yields a mixture of CaO and Mgo. If the weight of the combined oxides is

ExtremeBDS [4]

Answer:

38.83 % of CaCO3

61.17 % of MgCO3

Explanation:

where Moles of CaCO3 is equals to x and MgCO3 is y we have that...

CaCO3 molar mass = 100.09 g / mol = 100.09 x

MgCO3 molar mass = 84.31 g / mol = 84.31 y

decomposition reactions :

CaCO3 ---> CaO + CO2

MgCO3 ---> MgO + CO2

So we have that , Moles of CaO = Moles of CaCO3 = x

and Moles of MgO = Moles of MgCO3 = y

CaO molar mass = 56.08 g / mol

MgO molar mass = 40.30 g / mol

CaO = 56.08 x

MgO = 40.30 y

"If the weight of the combined oxides is equal to 51.00% of the initial sample weight,"

total mass of MgO and CaO = 51.00 % of Total Mass of MgCO3 and CaCO3

thus

56.08 x + 40.30 y = 0.51 ( 100.09 x + 84.31 y )

56.08 x + 40.30 y = 51.04 x + 42.99y

5.04 x = 2.7 y

y = 1.87 x

CaCO3 % in the sample

= 100.09 x × 100 / ( 100.09 x + 84.31 y )

= 10009 x / ( 100.09 x + 84.31 × 1.87 x )

= 10009 x / ( x ( 100.09 + 157.66 ) )

= 10009 / 257.75

= 38.83 %

MgCO3 % in the sample

= 100 - 38.83

= 61.17 %

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