There is no one answer (ordered pair) to this equation and the answer is found by graphing or trying out different values for each variable. Anyway, here are some solutions; (1,0), (4,1), (0,-1/3).
Step-by-step explanation:
There are 12 games in the population. You need to use a random number generator to choose 2 of these games.
RandomSample[{1,2,3,4,5,6,7,8,9,10,11,12},2]
Let's say the first sample you get is {1,5}. That corresponds to game times of 8 minutes and 7 minutes. The mean game time for that sample is 7.5 minutes. So the first row in your table would be:
![\left[\begin{array}{ccc}Sample&List\ of\ Game\ Times&Mean\ Game\ Time\\1&8,7&7.5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7DSample%26List%5C%20of%5C%20Game%5C%20Times%26Mean%5C%20Game%5C%20Time%5C%5C1%268%2C7%267.5%5Cend%7Barray%7D%5Cright%5D)
Answer:
h(0)= -7
Step-by-step explanation:
that is my answer
2s+5<span>≥49
First: Subtract 5 on both sides
You'll get: 2s </span><span>≥ 44
Last: Divide each side by 2 so your s would be alone
You'll get: s </span><span>≥ 22 <That would be your answer
HOPE THIS HELPS! ^_^</span>
Answer:
<h2>L.A. = 384 cm²</h2><h2>S.A. = 640 cm²</h2>
Step-by-step explanation:
Lateral Area:
We have four congruent triangles with base b = 16cm and height h = 12cm.
The formula of an area of a traingle:

Substitute:


Surface Area:

In the base we have the square with side s = 16cm. The formula of an area of a square:

Substitute:

