The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer: 9b+4n+6d+7
Step-by-step explanation:
1. 9b+9+4n−4+6d+2
2. 9b+4n+6d+(9-4+2)
3. 9b+4n+6d+7
Answer:
Quadrant 4
Step-by-step explanation:
The x value is positive so it is either in 1 or 4
The y value is negative so it is either 3 or 4
To meet both conditions, it must be 4
Answer:
C.60
Step-by-step explanation:
Just multiply 300 by 9 and then divide by 45.
Answer
False
Step-by-step explanation:
