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nevsk [136]
2 years ago
15

a woman 1.65. tall stood 50m away from the foot of a tower,and observe that the angle of elevation of the top of the tower to be

50⁰ what is the height of the tower​
Mathematics
2 answers:
ElenaW [278]2 years ago
5 0

\sf\huge\underline{\star Solution:-}

\rightarrowLet the women's height be AE and distance between the women and tower be AC.

Also let the height of tower be BC.

\rightarrowNow, clearly it is forming a triangle.

So, in triangle ABC,

\rightarrow\sf{Tan50° \:= \: \frac{BC}{AC}}

\rightarrow\sf{1.19 \:= \: \frac{BC}{50}}

\rightarrow\sf{1.19 ×50\:= \: BC}

\rightarrow\sf{59.5m\:= \: BC}

\rightarrowHence, BC = 59.5m

So, BD(total height of the tower)\sf{ = \:BC+CD}

\sf{= \:59.5+1.65}

\sf{=\: 61.15m}

Therefore, total height of the tower =\sf\purple{ 61.15m.}

________________________________

Hope it helps you:)

tangare [24]2 years ago
5 0

Answer:

61.24 m to the nearest hundredth.

Step-by-step explanation:

tan 50 = H / 50  

H =  50 tan 50

Height of the tower = H + height of the woman

= 50 tan 50 + 1.65

= 61.2377 m

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