Ask question

Ask question

All categories

3 years ago

11

What is the surface area of the box 12in 4in 3in

1 answer:

Slav-nsk [51]3 years ago

5 0

Find the area of the base:
(4)(3) = 12sqft
Find the area of the sides:
(4)(12) = 48sqft
There are 2 bases and 4 sides, therefore:
12(2) + 48(4) = 24 + 192 = 216sqft
Hope this helps :)

You might be interested in

As a bicycle salesperson, Norman earns a fixed salary of $20 per week plus $6 per bicycle for the first 6 bicycles he sells, $12

wlad13 [49]

Answer:

A. I only

I. y>2x

Step-by-step explanation:

I. y>2x

He sold x bicycles last week and y bicycles this week, this week, he earned more than twice as much as he did last week. Therefore more than twice means greater than 2 x or

y>2x

II. y>x This is not true because y could be greater than x and less than twice of x (2x)

III. y>3 This is also not true because the least he would be earning would be $ 20 and he could get earn greater than 3 and less than $ 20 which would again be contradictory to the given statement

4 0

3 years ago

Please I need help on this ASAP

Virty [35]

Answer:

True, False, True, False, False

Step-by-step explanation:

6 0

3 years ago

If Y varies directly with X solve the following :

BARSIC [14]

Answer:

a) x = -270

b) y = 304/9 or y = 33.78

c) x = -37.8

Step-by-step explanation:

y varies directly with x so y = kx

a)

y = kx

k = y/x

k = 10/-30 = -1/3

So

y = -1/3 x

If y = 90 then

90 = -1/3 x

x = 90 *(-3) = -270

b)

k = y/x

k = -19/-4.5

k = 38/9

So

y = 38/9 x

If x = - 8 then

y = 38/9 *(-8)

y = 304/9 or y = 33.78

c)

k = y/x

k = -4.3 / 12.9

k = - 1/3

So

y = -1/3 x

If y = 12.6 then

12.6 = -1/3 x

x = 12.6 *(-3)

x = -37.8

5 0

3 years ago

What is the factores form of (2x^2+11x-40)?

Cerrena [4.2K]

${2x}^{2} + 11x - 40 \\ = (2x - 5)(x + 8)$

Hope this helps. - M

7 0

3 years ago

Please please please need help on 3 and 4 I’m really lost on them

Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, $\frac{1}{2}$ , $\frac{1}{2}$ , 2,2)

Step-by-step explanation:

Given polynomial function is $f(x)=x^5-3x^3-2$

To find zeros equate f(x) to zero ie., $f(x)=0$

$x^5-3x^3-2=0$

By synthetic division

| 1 0 -3 0 -2

-1 | 0 -1 1 2 2

|_________________

1 -1 -2 2 0

Therefore x=-1 is a zero

$x^3-x^2-2x+2=0$

| 1 -1 -2 2

1 | 0 1 0 2

|___________________

1 0 -2 0

x=1 is the zero

$x^2 -2 =0$

$x=\pm\sqrt{2}$

$x=\sqrt{2}$ and

$x=\sqrt{-2}$

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is $f(x)=(x-4)(2x-1)^2(x-2)^2$

To find zeros equate f(x) to zero ie., $f(x)=0$

$(x-4)(2x-1)^2(x-2)^2=0$

$(x-4)=0$ (or) $(2x-1)^2=0$ or $(x-2)^2=0$

Therefore x=4, $x=\frac{1}{2}$ of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, $\frac{1}{2}$ , $\frac{1}{2}$ , 2,2)

5 0

3 years ago