Answer:
![3.67\cdot 10^{-5} J/m^3](https://tex.z-dn.net/?f=3.67%5Ccdot%2010%5E%7B-5%7D%20J%2Fm%5E3)
Explanation:
First of all, we need to calculate the magnetic field magnitude at 25 cm from the wire, which is given by
![B=\frac{\mu_0 I}{2\pi r}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%5Cmu_0%20I%7D%7B2%5Cpi%20r%7D)
where
μ0 = 4π × 10-7 t · m/a is the vacuum permeability
I = 12 A is the current in the wire
r = 25 cm = 0.25 m is the distance from the wire
Substituting,
![B=\frac{(4\pi \cdot 10^{-7})(12)}{2\pi(0.25)}=9.6\cdot 10^{-6} T](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%284%5Cpi%20%5Ccdot%2010%5E%7B-7%7D%29%2812%29%7D%7B2%5Cpi%280.25%29%7D%3D9.6%5Ccdot%2010%5E%7B-6%7D%20T)
Now we can calculate the energy density of the magnetic field, which is given by
![u = \frac{B^2}{2\mu_0}](https://tex.z-dn.net/?f=u%20%3D%20%5Cfrac%7BB%5E2%7D%7B2%5Cmu_0%7D)
And substituting, we find
![u = \frac{(9.6\cdot 10^{-6})^2}{2(4\pi \cdot 10^{-7})}=3.67\cdot 10^{-5} J/m^3](https://tex.z-dn.net/?f=u%20%3D%20%5Cfrac%7B%289.6%5Ccdot%2010%5E%7B-6%7D%29%5E2%7D%7B2%284%5Cpi%20%5Ccdot%2010%5E%7B-7%7D%29%7D%3D3.67%5Ccdot%2010%5E%7B-5%7D%20J%2Fm%5E3)
He needs to make sure he is consuming more than he is burning off
To find out scientific notation, you want to make sure that number is less than 10. So do 5.000000, you don't rally need the zeros but I just want to make my point. So use 10^x meaning ten the whatever power adds zeros like 5.000000x10^6 meaning it is increasing it by six zeros moving it out of the decimals and letting become 5,000,000.
Gas has no certain shape However, its Volume can change with Differences in Heat and Pressure.