- The bullet can travel about distance of (2115 m)
- Velocity can be regarded as the ratio of distance to time
- Velocity= (distance / time)
Given: velocity= 450 m/s
Time= 4.7s
- Distance= ( velocity × time)
<em>If we substitute the values</em>
= 2115 m
Therefore, the bullet can travel about 2115 m
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Answer:
m = 50 [kg]
Explanation:
The potential energy can be calculated by means of the following equation.
where:
Ep = potential energy = 735 [J]
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 1.5 [m]
Now replacing:
Answer:
magnitude of the pressure on the sail in the vicinity of Earth’s Orbit=
Explanation:
The momentum of a photon is:
p = E/c
E = the photon energy
c = the speed of light.
take the time derivative (gives the force)
F = dp/dt = (dE/dt)/c
F = 2(dE/dt)/c (is doubled for complete reflection of the light)
Intensity has the units of energy per unit time per unit area
= I
then,
Force/unit area = 2I/c
magnitude of the pressure on the sail in the vicinity of Earth’s Orbit=
Incomplete question as we have not told to find what.So the complete question is here
A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of mass m, moves with velocity (-60 m/s)i and a second piece, also of mass m, moves with velocity (-60 m/s)j. The third piece has mass 3m.Just after the explosion, what are the (a) magnitude and (b) direction of the velocity of the third piece?
Answer:
Explanation:
Given data
The vessel at rest
Piece one,of mass m,moves with velocity=(-60 m/s)i
Piece two,of mass m,moves with velocity=(-60 m/s)j
Piece three,of mass 3m
As the linear momentum is conserved in this system,Because the system is closed and no external force acting on it
So momentum is given as
As the vessel at rest so the initial momentum is zero
So