Because of the build up of pressure. There is so much steam coming from such a compressed point, it’s coming out in force.
Now think of that same spot being closed, it only has one place to go but it can’t leave, so that pressure will build and build and then BOOM, it explodes.
In short, the answer is the pressure being released from a small point, and how that energy is released.
Explanation:
Let us assume that the maximum allowable horizontal distance be represented by "d".
Therefore, torque equation about A will be as follows.

d = ![\frac{[2 \times 75 \times (0.7+0.15+0.15) - 60 \times 0.15 - 252 \times 0.15 \times 2]}{252}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2%20%5Ctimes%2075%20%5Ctimes%20%280.7%2B0.15%2B0.15%29%20-%2060%20%5Ctimes%200.15%20-%20252%20%5Ctimes%200.15%20%5Ctimes%202%5D%7D%7B252%7D)
d = 0.409 m
Thus, we can conclude that the maximum allowable horizontal distance from the axle A of the wheelbarrow to the center of gravity of the second bag if she can hold only 75 N with each arm is 0.409 m.
Answer:
Here, force=20N and displacement=10m
Work=Force×Displacement=20N×10m=200Nm
<span>One thousand grams of seawater has 35 grams of dissolved substances ... on the average. While the salinity of the Earth's oceans and seas varies, the average salinity of seawater rests at 3.5%. Consider one liter or sea or ocean water. One liter has 1,000 milliliters (mL) in it. To find 3.5% of 1,000, we would multiply with the decimal place adjusted for percentages: 1000 x .035 = 35. Therefore, for every 1,000 mL of seawater, we will find 35 grams of (mostly) sodium chloride, otherwise known as salt.</span>
Answer:
<em>20.08 Volts</em>
Explanation:
<u>Parallel Connection of Capacitors</u>
The voltage across any two elements connected in parallel is the same. If the elements are capacitors, then each voltage is


They are both the same after connecting them, thus

Or, equivalently

The total charge of both capacitors is

We can compute the total charge by using the initial conditions where both capacitors were disconnected:

Now we compute Q1 from the equation above

The final voltage of any of the capacitors is
