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julia-pushkina [17]
3 years ago
13

What is the plce and value of the 2's in the#24229582

Mathematics
2 answers:
maks197457 [2]3 years ago
4 0
1. 20,000,000 = 20 million
2. 200,000 = 200 thousand
3. 20,000 = 20 thousand
4. 2 = 2 ones? (I'm not sure about this one)
Lera25 [3.4K]3 years ago
4 0
#1 20,000,000 = 20 million
#2 200,000 = 200 thousand
#3 20,000 = 20 thousand
#4 2 = 2 ones
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How do I do this question?
Liula [17]
It's impossible because there are no like terms.
6 0
3 years ago
Read 2 more answers
A student has earned scores of 87, 81, and 88 on the first 3 of 4 tests. If the student wants an average (arithmetic mean) of ex
Juli2301 [7.4K]
To find an average you take the numbers to be averaged and add them together then You take the number and divide it by the number of numbers, in this case 4, and that gives you the average.
on this problem you want to do the opposite. you know the average she wants, an 87, so you multiply it by 4. 87*4=348. then you add the three numbers you have (88,81 and 87) and you get 256.
then you subtract 256 from 348 and you get 92. 92 is your answer to check just add 87+81+88+92=348
348/4=87
87 was the average she wanted.
Hope this helped! good luck :)
4 0
3 years ago
Evaluate the expression 2m+2n if m=9 and n=3
tatuchka [14]
Just substitute each number in for the variables: 9 for m and 3 for n.

2m+2n
= 2(9)+2(3)
= 18+6
= 24
4 0
3 years ago
Read 2 more answers
1. Make sure your answers and work is SHOWN please and steps are in order.
JulijaS [17]

Been a while since I've done synthetic division.

1a. Let's assume that's supposed to be an equals sign

p(x) = 2x⁴ - 3x³ - 6x² + 5x + 6

possible rational roots have factors of 6 in the numerator and of 2 in the denominator.  We'll only worry about negative numerators.

Factors of six: 1,2,3,6, and we don't forget -1,-2,-3,-6

Factors of 2: 1,2

Possible rational roots:

(dividing by 1:) 1,-1,2,-2,3,-3,6,-6

(dividing by 2:) 1/2, -1/2  (2/2=1 is a duplicate, don't have to repeat it), 3/2, -3/2

Possible rational roots: 1,-1,2,-2,3,-3,6,-6, 1/2, -1/2, 3/2, -3/2

Synthetic division, trying x=1,

   1 | 2  -3  -6  5  6

             2  -1  -7  -2

       2    -1  -7  -2  4

Got a remainder of 4, so 1 isn't a root;

Trying x=-1  

-1 | 2  -3  -6  5  6

         -2   5  1  -6

     2  -5  -1  6  0

Zero remainder, found a root, x=-1.  This division says

(2x⁴ - 3x³ - 6x² + 5x + 6) / (x + 1) = 2x³ - 5x² - x + 6

Same set of rational roots on the cubic, we continue with x=2

2 | 2 -5 -1 6

         4 -2 -6

    2  -1 -3 0

Another zero remainder, x=2 is a root.  We're left with 2x² - x - 3 = 0, which factors as

(2x - 3)(x + 1) = 0

That's a second factor of x+1.  Our final factorization is

2x⁴ - 3x³ - 6x² + 5x + 6 = (x + 1)²(x-2)(2x - 3)

Fourth degree with a positive leading coefficient so goes to +infinity at both ends.  Double zero at x=-1, so it's tangent there, just touching the x axis, then down through x=3/2 and up through x=2.  

I'll leave the actually sketching and the other two polynomials to you -- that took some time.

4 0
3 years ago
Select the polynomial that is a perfect square trinomial.
Alina [70]

Answer:

  16x^2 -8x +1

Step-by-step explanation:

The square of a binomial expands as ...

  (a +b)^2 = a^2 +2ab +b^2

So, you need to look for a trinomial with first and last terms that are perfect squares and a middle term that is double the product of the roots of those terms.

This pattern matches ...

  16x^2 -8x +1 = (4x -1)^2

6 0
3 years ago
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