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3 years ago

Balance this equation: HgO ---> 2Hg + O2

Mathematics

1 answer:

lesantik [10]3 years ago

7 0

Answer:

I think it's

2 HgO (s) → 2 Hg (l) + O2 (g)

Step-by-step explanation:

This is an oxidation-reduction (redox) reaction:

2 HgII + 4 e- → 2 Hg0

(reduction)

2 O-II - 4 e- → 2 O0

(oxidation)

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A car is rated to get 28 miles per gallon. How far can it travel on 12.5 gallons of gas?

Eddi Din [679]

28m : 1gal

x : 12.5gal

28 * 12.5 = 350

350m : 12.5gal

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3 years ago

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Given that x equals 6 and y equals -4

aleksandr82 [10.1K]

Answer: 42/12 or 3.5

Step-by-step explanation:

5(6)/3(-4)= -30/12

-30/12 + 6 or -30/12 + 72/12 = 42/12 or 3.5

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3 years ago

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Solve -2z – 5 > 3 for z.

Natasha2012 [34]

Hi,

- 2z - 5 > 3

- 2z > 8

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3 years ago

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Lois makes customised tee-shirts. She advertises and receives orders through her own website. She buys blank tee-shirts for $1 e

Kay [80]

Lois will sell her tee-shirt for $13.20

The percentage profit = $\frac{profit}{cost price}$ × 100

Profit = Selling price - cost price

Cost price is the total amount expended in making the tee-shirts

cost price includes cost of buying blank shirt , cost of fabric paint and amount Lois pay herself

cost of buying blank shirt = $1

cost of fabric paint = $1

amount Lois pay herself = $1\frac{1}{2}$ x $6

$\frac{3}{2}$ x $6 = $9

Total cost price = $1 + $1 + $9 = $11

0.2 = $\frac{profit}{11}$

profit = 11 x 0.2 = $2.2

$2.20 = selling price - $11

selling price = $11 + 2.20 = $13.20

To learn more about selling price, please check : brainly.com/question/15533091?referrer=searchResults

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3 years ago

A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0

3 years ago