The quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3
<h3 /><h3>How to solve fraction</h3><h3 />
n³ / (2n - 6) ÷ n³ / (3n - 9)
- multiply by the reciprocal of n³ / (3n - 9)
= n³ / (2n - 6) × 1 / n³ / (3n - 9)
= 2n - 6 / 3n - 9
= 2(n - 3) / 3(n - 3)
= 2/3
Therefore, quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3
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Answer:
Should be A.
Step-by-step explanation:
idk how I got it tbh
Answer:
2 is the only when prime number
