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balandron [24]
4 years ago
14

Round 100,592 to the nearest 10,000

Mathematics
1 answer:
Nitella [24]4 years ago
5 0

It's 100,000

<em>Have a great Day!</em>

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Ghella [55]
5(4)+5x=60
x=8
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Simplify. rewrite the expression in the form 8n. (8^-8(8^3)
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I’m not sure but I got 8 ^-5
4 0
3 years ago
Solve for x:<br> I need a answer with an explanation. Algebra 1
kirill115 [55]

Answer: x = -1

Step-by-step explanation:

You need to convert to the same base

\frac{1}{16}  = \frac{1}{2^{4} } = 2^{-4}

So

2^{-4} = 2^{-2x-6}

For these values to be equal, the exponents have to be equal

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3 0
3 years ago
A restaurant sells about 330 sandwiches each day at a price of $6 each $.25 decrease in price. 15 more sandwiches are sold per d
zmey [24]

Answer:

restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

Step-by-step explanation:

to calculate current revenue= $6 x 330 = $1980

suppose x as the number of times the price to be dropped by $0.25

then find new price.. i.e

new price= $(6-0.25x)

and, new sell=330 +15x sandwiches

therefore, the new revenue would be= (6-0.25x)(330 +15x)

in order to maximize the current revenue, simplify the above equation and make it complete square using x

(6-0.25x)(330 +15x)

=1980-82.5x +90x -3.75x^{2}

=1980 + 7.5x -3.75x^{2}

=1980-3.75 (-2x+x^{2}) ----> taking out common

now, to make a complete square lets add and subtract 1 inside the parentheses

=1980-3.75(-1+1-2x+x^{2})

=1980 +3.75 -3.75(x^{2} -2x +1)

=1983.75 -3.75 (x-1)^{2}---->(1)

as (x-1)^{2} is positive always, minimize the other term in order to maximize the total revenue.

so the minimum possible value of (x-1)^{2} = 0

therefore, x=1

putting x in eq(1) the revenure becomes,

$(1983.75-0)=> $1983.75

therefore, restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

3 0
3 years ago
(3?2)+(4?1)to the power of 2=10
Advocard [28]
Sol_

( 3 - 2 ) + ( 4 - 1 ) ^ 2

= 1 + 3^2

= 1 + 9

= 10

Answer is " - " .

hope it helped !

Thanks!

3 0
3 years ago
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