What equation can I make out of this problem

1. Determine the measure of the unknown angles indicated by letters. Justify your answers with

Maurinko [17]

Answer:

hello,

Step-by-step explanation:

a)

In an isocele triangle, base's angles have the measure:

42+2a=180

2a=180-42

a=69(°)

b)

in a triangle, an external angle has for measure the sum of the angles not adjacents.

55+b=132

b=77 (°)

c)

in a quadrilater the sum of the (interior) angles is 2*180=360 degrees.

90+90+68+c=360

c=360-90-90-68

c=112 (°)

7 0

2 years ago

Compare the function

krek1111 [17]

They all have the same y-intercept

8 0

3 years ago

F + 2.5= 3f + 7.24 (What first step would you do to solve for f? )

Step2247 [10]

Step-by-step explanation:

We have our question.

f + 2.5= 3f + 7.24

Then you combine like terms that taking the coefficients apart.

That is,

NOTE: WHEN TAKING A NUMBER ACROSS AND EQUAL SIGN THE SIGN CHANGES, E.G - TO + .

f - 3f = 7.24 - 2.5

-2f = 4.74

Divide both sides by coefficient of f which is -2

-2f = 4.74

-2 -2

f = 8.49

8 0

2 years ago

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Expand and simplify 3(x-2) + 2(4x-1)

Zanzabum

Answer:

11x-8

Step-by-step explanation:

$3(x - 2) + 2(4x - 1) \\ multiply \: inside \: the \: bracket \\ 3x - 6 + 8x - 2 \\ 11x - 8$

3 0

1 year ago

A company manufactures running shoes and basketball shoes. The total revenue (in thousands of dollars) from x1 units of running

Alborosie

Answer:

$x_1 =2 , x_2=7$

Step-by-step explanation:

Consider the revenue function given by $R(x_1,x_2) = -5x_1^2-8x_2^2 -2x_1x_2+34x_1+116x_2$ . We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).

$\frac{dR}{dx_1} = -10x_1-2x_2+34 =0$

$\frac{dR}{dx_2} = -16x_2-2x_1+116 =0$

From the first equation, we get, $x_2 = \frac{-10x_1+34}{2}$ .If we replace that in the second equation, we get

$-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156$

From where we get that $x_1 = \frac{156}{78}=2$ . If we replace that in the first equation, we get

$x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7$

So, the critical point is $(x_1,x_2) = (2,7)$ . We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives and check if the criteria is fulfilled in order for it to be a maximum. We get that

$\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}$

$\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16$

We have the following matrix,

$\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right]$ .

Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is $(-10)\cdot (-16) - (-2)(-2) = 156>0$ and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum

8 0

3 years ago

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