By solving the equation
1/2 +x =4/7
x = 4/7 -1/2
x= 1/14
<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>
The first answer is C. I can't read the second, try retyping it here?
Since x is across from 148, and arcs opposite inscribed angles = 2×angle, then we can find x first.
We could set the 2 angles equal to 180 or their arcs equal to 360.
360 - (2×148) = x-arc
x-arc = 360 - 296 = 64
x = x-arc ÷2 = 64/2 = 32
Now for angle A we plug in for x:
A = 2x+1 = 2(32)+1 = 65°
