Step-by-step explanation:
(3x+3)(x+2)=
3x^2+6x+3x+6
=3x^2+9x+6
we get quadratic equation
find discriminant:
D=b^2-4ac=81-72=9
x=(-b±√D)/2a
x1=-6/6=-1
x2=-12/6=-2
one of the x values should be correct.
but why when I try to put values I get zero
Answer:
If the question comes from a textbook
Step-by-step explanation:
use slader
give us a problem or somen
Step-by-step explanation:
Answer:
245 square inches
Step-by-step explanation:
4(1/2×7×14)+(7×7)
To solve for this, we need to find for the value of x
when the 1st derivative of the equation is equal to zero (or at the
extrema point).
So what we have to do first is to derive the given
equation:
f (x) = x^2 + 4 x – 31
Taking the first derivative f’ (x):
f’ (x) = 2 x + 4
Setting f’ (x) = 0 and find for x:
2 x + 4 = 0
x = - 2
Therefore the value of a is:
a = f (-2)
a = (-2)^2 + 4 (-2) – 31
a = 4 – 8 – 31
a = - 35
