Answer:
it's true! it's easier to solve for y because there's no coefficient in front of it unlike the second one that has "9y."
Answer:
47.0
Step-by-step explanation:
In this right angle triangle, we are faced with a challenge of two sides. The opposite side and the adjacent side, hence the tangent is used.
Where it is the opposite side and hypothenus side, the sine is used and when it is the hypothenus side and adjacent side, the cosine is used.
Hence, we have tan62°=x/25
We cross multiply, to have
25(tan 62°)= x
x = 47.01816
In rounding up numbers, number 1 to 4 will be rounded up to zero, while numbers 5 to 9 will be rounded up to 1.
Rounding up 47.01816 to the nearest tenth. The tenth value is the figure is 0, before it we have 1, which is to hundredth. 1 will be rounded up to zero.
So we have 47.0
Answer:
0.55
Step-by-step explanation:
5 divided by 9 = 0.55
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)

So the value of the element in the position
is 15

So the value of the element in the position
is 14
Then with these two values you can determinate the result matrix.
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Multiples of 8 are basically the result of counting by 8's. (Technically, multiples are a set of number which can be divided by a certain number without a remainder.)
The first 4 multiples of 8 are {

}.