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2 years ago

9

(Repost) School is starting, and the teacher is giving each student 2 new pencils. She has 8 rows with 4 desks in each row. Whic

h method (s) below will show her how many pencils she will need?
A. 2 x 8 + 16, 16 x 4
B. 2 x 4 + 8, 8 x 8
C. 4 x 8 + 32, 2 x 32
-------------------------------------
A. Only method A
B. Only method A and B
C. Only method B and C
D. Only method A, B, and C

2 answers:

liubo4ka [24]2 years ago

7 0

A

2 x 8+16 = 32 16 x 4 = 64

B

2 x 4 +8 = 16 8 x 8 = 64

C

4 x 8 + 32 = 64 2 x 32 = 64

1 l l l l 8 5 l l l l 40

2 l l l l 16 6 l l l l 48

3 l l l l 24 7 l l l l 56

4 l l l l 32 8 l l l l 64

The teacher has 64 or more pencils to give out.

<em>Hope this helps you choice your answer. :) </em>

creativ13 [48]2 years ago

5 0

D.) only method A, B, and C,

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4/5 divided by 1/3 plus 1/5 minus 3/5

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Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

as

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

so

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

so

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

so

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

so

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

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90% = 0.90

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So what is the question in this?

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HELP ASAP PLEASE I NEED ANS N SOLUTION

Blababa [14]

Given:

A bowl contains 25 chips numbered 1 to 25.

A chip is drawn randomly from the bowl.

To find:

The probability that it is

a. 9 or 10?

b. even or divisible by 3?

c. divisible by 5 and divisible by 10?

Solution:

a. We have,

Number of total chips = 25

Favorable out comes are either 9 or 10. So,

Number of favorable outcomes = 2

The probability that the selected chip is either 9 or 10 is:

$\text{Probability}=\dfrac{\text{Number of favorable outcomes}}{\text{Number of total outcomes}}$

$\text{Probability}=\dfrac{2}{25}$

Therefore, the probability that the selected chip is either 9 or 10 is $\dfrac{2}{25}$ .

b. The numbers that are even from 1 to 25 are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24.

The numbers from 1 to 25 that are divisible by 3 are 3, 6, 9, 12, 15, 18, 21, 24.

The numbers that are either even or divisible by 3 are 2, 3, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24.

Number of favorable outcomes = 16

The probability that the selected chip is either even or divisible by 3 is:

$\text{Probability}=\dfrac{16}{25}$

Therefore, the probability that the selected chip is either even or divisible by 3 is $\dfrac{16}{25}$ .

c. The numbers from 1 to 25 that are divisible by 5 are 5, 10, 15, 20, 25.

The numbers from 1 to 25 that are divisible by 10 are 10, 20.

The numbers that are divisible by both 5 and 10 are 10 and 20.

Number of favorable outcomes = 2

The probability that the selected chip is divisible by 5 and divisible by 10 is:

$\text{Probability}=\dfrac{2}{25}$

Therefore, the probability that the selected chip is divisible by 5 and divisible by 10 is $\dfrac{2}{25}$ .

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Step-by-step explanation:

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