The measure of the angle <JKL is 56 degrees
<h3>Tangent secant theorem of a circle</h3>
The theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.
Given the following parameters
m<IL = 112 degrees
Since the measure of the vertex is half the measure of its intercepted arc, hence;
<JKl = 1/2(m<IL)
Substitute the given parameters into the formula to have;
<JKl = 1/2(112)
<JKL = 56 degrees
Hence the measure of the angle <JKL is 56 degrees
Learn more on Tangent secant theorem here: brainly.com/question/26826991
#SPJ1
Answer:
Divide both sides by 3.
(x+2)^2=16
Square root both sides.
x+2= ± 4 (plus OR minus, can be either so we have to include both)
Minus 2 from both sides.
x=-2 ± 4
Add and minus the 4 to -2.
x = -2-4 = -6 and x=-2+4 = 2
<u>biomass can be converted directly into liquid fuels, called "biofuels," to help meet transportation fuel needs. The two most common types of biofuels in use today are ethanol and biodiesel, both of which represent the first generation of biofuel technology.</u>
The question is worded a bit strangely (in my opinion anyway), but I think your teacher wants you to describe how exponents work.
Let's say we had the expression 
The base is 5 as its the bottom most value (think of something like the base of a tree or building). The exponent is 3.
The exponent of 3 tells the reader to multiply the base 5 by itself 3 times like so
With larger exponents, it becomes more tedious to write out all the repeated multiplications, which is why many calculators have an exponent button to save time.
The given equation is a Quadratic equation, so it's graph must be a parabola, and the Coefficient of x² is positive that means the parabola must have an opening upward.
And 2 is added to the ideal equation, so the parabola must have shift 2 units up from x - axis.
From the above information, we can easily conclude that the Correct representation is done in graph 4
