U would replace x with 0 in the equation and solve and then do the same but with y and those are ur x and y values of ur point
Ex: 2x+5y=15
2(0) +5y=15
5y=15
Y=3
2x+5(0)=15
2x=15
X=7.5
So ur point would be (7.5,3)
Here we will use the trial and error method.
- We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>





<h2>Now,</h2><h3>x=2</h3>




<h2>Again,</h2><h3>x=3</h3>




<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>