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Ludmilka [50]
2 years ago
7

What is the value of this expression? {5×(13−8)}+12÷6

Mathematics
1 answer:
Tom [10]2 years ago
6 0

\qquad\qquad\huge\underline{{\sf Answer}}

Let's evaluate ~

\qquad \tt \dashrightarrow \: \{5 \times (13 - 8) \} + 12 \div 6

\qquad \tt \dashrightarrow \: \{5 \times (5) \} + 12 \div 6

\qquad \tt \dashrightarrow \: \{5 \times 5\}  + 2

\qquad \tt \dashrightarrow \:25 + 2

\qquad \tt \dashrightarrow \:27

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What are the domain and range of f(x) = 2|x -4|? <br> plz i'm in need
mafiozo [28]

Answer:

Domain: (-∞, ∞)

Range: [0, ∞)

Step-by-step explanation:

The domain represents what x can be. In this scenario, we do not have x as a denominator, and there is nothing limiting x, so its domain is (-∞, ∞)

The range represents what f(x) can be, Because |x-4| is in absolute value, the lowest |x-4| can be is 0, and as a result, the lowest value of 2|x-4| is 2*0=0. The maximum value of f(x) is ∞ as an absolute value does not limit the maximum, making the range [0, ∞)

6 0
3 years ago
30 POINTS!!! NEED HELP!!!!
Kaylis [27]

Answer:

b) 16 + 9 + 4 + 1 + 0 + 1 + 4 + 9 + 16 + 25 + 36 + 49 + 64 + 81 + 100 + 121

Step-by-step explanation:

\Sigma_{k=1}^{16} (k - 5)^2 \\= (1- 5)^2 +  (2- 5)^2 +  (3- 5)^2 + \\ (4- 5)^2 +  (5- 5)^2 +  (6- 5)^2 \\+  (7- 5)^2 +  (8- 5)^2 +  (9- 5)^2 \\+  (10- 5)^2 +  (11- 5)^2 +  (12- 5)^2 \\+  (13- 5)^2 +  (14- 5)^2 +  (15- 5)^2\\ +  (16- 5)^2 \\\\=(-4)^2 +  (-3)^2 +  (-2)^2 +  (-1)^2 +  (0)^2 \\+  (1)^2 +  (2)^2 +  (3)^2 +  (4)^2 +  (5)^2 \\+  (6)^2 +  (7)^2 +  (8)^2 +  (9)^2 +  (10)^2 + \\ (11)^2 \\\\=16 + 9 + 4 + 1 + 0 + 1 + 4 + 9 + 16 + 25 \\+ 36 + 49+ 64 + 81 + 100 + 121

6 0
4 years ago
Use Lagrange multipliers to find the maximum and minimum values of
marusya05 [52]

The Lagrangian is

L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)

It has critical points where the first order derivatives vanish:

L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}

L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y

L_\lambda=x^2+y^2-4=0

From the first two equations we get

-\dfrac1{2x}=-\dfrac4y\implies y=8x

Then

x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}

At these critical points, we have

f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125 (maximum)

f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125 (minimum)

5 0
4 years ago
Jina and her husband are each starting a saving plan. Jina will initially set aside $650 and then add $135 every month to the sa
Basile [38]

Step-by-step explanation:

If A=650+135N; and B=585N,

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T=720N+650

4 0
3 years ago
If you deposit $25,000 now at 6.5% compounded quarterly, how much will you have in 30 years?
Mice21 [21]

Answer:

$172,984.44

Step-by-step explanation:

We can use the formula

A = P(1 + \frac{r}{n})^{nt} to compute the final amount

Here P is the principal amount, the original deposit = $25,000

r is the annual interest rate = 6.5% = 0.065 in decimal

n is the number of times the compounding takes place. Here it is quarterly so it is 4 times a year

t is the number of time periods ie 30 years

A is the accrued amount ie principal + interest

Computing different components,

nt = 4 \times 30 = 120

r/n =  0.065/4 = .01625

1 + r/n = 1.01625

(1 + r/n)^{nt} = 1.01625^{120}

Therefore

A = 25000 \times 1.0625^{120} = 172,984.44


4 0
2 years ago
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