Hi there!

f(x) = 2x + 6
Differentiating 2x = 2 (Power rule, dy/dx xⁿ = nxⁿ⁻¹)
Differentiating a constant always equals 0.
Thus:
f'(x) = 2
Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!
This process is very simple. All you are doing is creating a table of values somewhere to help you graph this function. As you can see, the coordinates of
and
are all touched on this graph, letting you know that this information is accurate.
I am joyous to assist you at any time. ☺️
Simplies form of 3/8 is 1/4
Answer:
8x4x2=64+24=88 the answer is 88 yw :) pls give brainliest
Step-by-step explanation: