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alexira [117]
2 years ago
8

Help..please i dont understand this assignment

Mathematics
2 answers:
FrozenT [24]2 years ago
6 0

Answer

the second one, and 5th one

Step-by-step explanation:

because it is liquid

san4es73 [151]2 years ago
5 0
I think it’s A, B, C, D.
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Please help and explain with these 2 math questions!!!!!!
Volgvan

1)  -10x+y=4

Now, you should substitute x in every situation.

* x=-2 <em>=> -10*(-2)+y=4... 20+y=4... <u>y=-16</u></em>

<em />* x=-1 =>-10*(-1)+y=4... 10+y=4... <u>y=-6</u>

<u />*x=0 => -10*0+y=4... <u>y=4</u>

<u />* x=1 =>  -10*1+y=4... -10+y=4... <u>y=14</u>

<u />* x=2 => -10*2+y=4... -20+y=4... <u>y=24</u>

<u>2)</u> -5x-1=y

For example: x=0

-5*0-1=-1

<u>
</u>



6 0
3 years ago
Suppose that v is an eigenvector of matrix A with eigenvalue λA, and it is also an eigenvector of matrix B with eigenvalue λB. (
galben [10]

Answer:

(a) Yes, λ_{A}+λ_{B}

(b) Yes, λ_{A}λ_{B}

Step-by-step explanation:

First, lets understand what are eigenvectors and eigenvalues?

Note: I am using the notation λ_{A} to denote Lambda(A) sign.

v is an eigenvector of matrix A with eigenvalue λ_{A}

v is also eigenvector of matrix B with eigenvalue λ_{B}

So we can write this in equation form as

Av=λ_{A}v

So what does this equation say?

When you multiply any vector by A they do change their direction. any vector  that is in the same direction as of Av, then this v  is called the eigenvector of A. Av is λ_{A} times the original v. The number λ_{A} is the eigenvalue of A.

λ_{A} this number is very important and tells us what is happening when we multiply Av. Is it shrinking or expanding or reversed or something else?

It tells us everything we need to know!

Bonus:

By the way you can find out the eigenvalue of Av by using the following equation:

det(A-λI)=0

where I is identity matrix of the size of same as A.

Now lets come to the solution!

(a) Show that v is an eigenvector of A + B and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(A+B)(v)=Av+Bv=(λ_{A})v + (λ_{B})v=(λ_{A}+λ_{B})(v)

so,  (A+B)(v)=(λ_{A}+λ_{B})(v)

which means that v is also an eigenvector of A+B and the associated eigenvalues are λ_{A}+λ_{B}

(b) Show that v is an eigenvector of AB and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(AB)(v)=A(Bv)=A(λ_{B})=λ_{B}(Av)=λ_{B}λ_{A}(v)=λ_{A}λ_{B}(v)

so,  

(AB)(v)=λ_{A}λ_{B}(v)

which means that v is also an eigenvector of AB and the associated eigenvalues are λ_{A}λ_{B}

5 0
3 years ago
I need urgent help with this
natita [175]

Answer:

A

<em>good luck, i hope this helps :) </em>

<em />

5 0
3 years ago
Read 2 more answers
-6/5-2/3v+4/15+1/3v Combining like terms to create an equivalent expression
WINSTONCH [101]

Answer:

(-1/3)v - 14/15

Step-by-step explanation:

Group the v terms together and then the constant terms:

v(-2/3 + 1/3) + (-6/5 + 4/15)

This simplifies to:

  (-1/3)v + (-18/15 + 4/15), or

   (-1/3)v - 14/15

7 0
3 years ago
Does anyone know what this question means?
ioda

Answer:

Yes

Step-by-step explanation:

I know what it means. Trust me. I know.

7 0
4 years ago
Read 2 more answers
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