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Dvinal [7]
3 years ago
7

What is the solution to the system of equations below?

Mathematics
2 answers:
polet [3.4K]3 years ago
6 0

Answer:

X = 4 & Y = 3

Step-by-step explanation:

1. Multiply the first equation by -2 & Multiply the second equation by 1

-2 (2x+3y=17)

1  (3x+6y=30)  

Becomes:

−4x−6y=−34

3x+6y=30

Add these equations to eliminate y:

−x=−4

2. Then solve −x= −4 for x:

     −x=−4

    -x/−1 = −4/−1

(Divide both sides by -1)

x=4

Now that we've found x, plug it back in to solve for y.

Write down an original equation:

2x+3y=17

Substitute (4) for (x) in 2x+3y=17:

(2)(4)+3y=17

3y+8=17(Simplify both sides of the equation)

3y+8+−8=17+−8(Add -8 to both sides)

3y=9

3y/3 = 9/3

(Divide both sides by 3)

y=3

dalvyx [7]3 years ago
4 0

Answer:

What is the solution to the system of equations below?

2 x + 3 y = 17. 3 x + 6 y = 30.

(Negative 7, 24)

(3, 4)

(4, 3)

(24, Negative 7)

ANSWWER IS NUMBER 3 OR C

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Need help on number 1, 5 and 7
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
William and Emma go into a burger shop with a total of $40.00 to spend. Burgers cost $4.50 each and soft drinks cost $1.00 each.
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12 items in total

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Samuel needs 332 feet of wood to bulid a fence the wood comes in lengths of 15 feet .How many total piece of wood will samuel ne
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The table shows the American League batting champions for the years 1999–2003. The sum of these five batting averages is 1.754.
fgiga [73]
The answer is <span>A. .357 + .372 + .350 + .349 + x = 1.754; .326 
</span>
x1 - average of <span>1999 Nomar Garciaparra Boston
</span>x2 - average of 2000 Nomar Garciaparra Boston
x3 - average of <span>2001 Ichiro Suzuki Seattle 
</span>x4 - average of Manny Ramirez Boston  
x - average of <span>2003 Bill Mueller Boston 

</span><span>The sum of these five batting averages is 1.754:
x1 + x2 + x3 + x4 + x = 1.754

From the table:
x1 = 0.357
x2 = 0.372
x3 = 0.350
x4 = 0.349
x = ?

<u>0.357 + 0.372 + 0.350 + 0.349 + x = 1.754</u>

1.428 + x = 1.754
x = 1.754 - 1.428
<u>x = 0.326</u></span>
5 0
3 years ago
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