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Dvinal [7]
3 years ago
7

What is the solution to the system of equations below?

Mathematics
2 answers:
polet [3.4K]3 years ago
6 0

Answer:

X = 4 & Y = 3

Step-by-step explanation:

1. Multiply the first equation by -2 & Multiply the second equation by 1

-2 (2x+3y=17)

1  (3x+6y=30)  

Becomes:

−4x−6y=−34

3x+6y=30

Add these equations to eliminate y:

−x=−4

2. Then solve −x= −4 for x:

     −x=−4

    -x/−1 = −4/−1

(Divide both sides by -1)

x=4

Now that we've found x, plug it back in to solve for y.

Write down an original equation:

2x+3y=17

Substitute (4) for (x) in 2x+3y=17:

(2)(4)+3y=17

3y+8=17(Simplify both sides of the equation)

3y+8+−8=17+−8(Add -8 to both sides)

3y=9

3y/3 = 9/3

(Divide both sides by 3)

y=3

dalvyx [7]3 years ago
4 0

Answer:

What is the solution to the system of equations below?

2 x + 3 y = 17. 3 x + 6 y = 30.

(Negative 7, 24)

(3, 4)

(4, 3)

(24, Negative 7)

ANSWWER IS NUMBER 3 OR C

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