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professor190 [17]
2 years ago
12

cellus If investments double every 7 years and you start with a $600 investment, how much money would you have after 21 years? ​

Mathematics
1 answer:
Keith_Richards [23]2 years ago
6 0

Answer:

4800$

Step-by-step explanation:

1 day = 600

7 years = 600 x 2 = 1200$

14 years = 1200 x 2 = 2400$

21 years = 2400 x 2 = 4800$

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-51÷3=-17

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<span>Ivy has 4 tiles with pictures of plants and 5 tiles with pictures of animals. Ivy keeps all the tiles on a mat with the pictures hidden and mixes them up. She then turns one tile face up and finds the picture of a plant on it. She removes this tile from the mat and turns another over tile without looking. What is the probability that the second tile that Ivy turns over has a plant on it. To solve the problem the first step is to find out how many tiles are in total. Since one of the plant tiles were removed we have 3 left. 
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5 + 3 = 8

Now we find the percent by dividing 3 from 8. The top number is called  the NUMERATOR<span> and the bottom number is called the </span>DENOMINATOR<span>.</span>

3 ÷ 8 = 0.375

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Answer:

Option D.

Step-by-step explanation:

Minimize the objective function P = 5x + 8y for the given constraints.

x\geq 0,y\geq 0

2x+3y\geq 15

3x+2y\geq 15

The related equations of above inequalities are

2x+3y=15

3x+2y=15

For 2x+3y=15,

x     y

0     5

7.5   0  

Plot (0,5) and (7.5,0) and join them by straight line.

For 3x+2y=15,

x     y

0     7.5

5      0  

Plot (0,7.5) and (5,0) and join them by straight line.

Check the inequalities for (0,0).

2(0)+3(0)\geq 15\Rightarrow 0\geq 15 False

3(0)+2(0)\geq 15\Rightarrow 0\geq 15 False

It means both lines are solid lines and shaded region for each lies opposite side of (0,0).

From the below graph it is clear that the vertices of feasible region are (0,7.5), (3,3), (7.5,0).

Point       P = 5x + 8y

(0,7.5)     P=5(0)+8(7.5)=60

(3,3)     P=5(3)+8(3)=15+24=39

(7.5,0)     P=5(7.5)+8(0)=37.5 (Minimum)

So, minimum value is 37.5.

Therefore, the correct option is D.

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3 years ago
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