Answer:
Exact form: 
Decimal form: 
The solution for x is: The solution for x is of 10.455º
Step-by-step explanation:
We are given the following equation:

Placing into the desired format, the exact format is:

In the decimal part, we divide 8 by 9. So

Solving for x:
We apply the inverse sine. So




The solution for x is of 10.455º
B) the additive inverse of -3 is +3, so 17-(-3) = 20 is your answer.
Remember, two negatives = one positive, and so:
- (-3) = 3
17 + 3 = 20
Therefore, B is your answer
hope this helps
Answer:
110°
Step-by-step explanation:
128°+40°+82°+x°= 360°
so 250°+x°=360°
x°=360°-250°
x°=110°
For parts A, B, C, and D you most likely created a line. What question E is asking is for you to create a line that is perpendicular to the line you already created that also passes through the point (1,1). What is important to understand here is that the slope of the perpendicular line is the negative reciprocal of the original line's slope... if the original slope is (-4/3) than the perpendicular slope is (3/4)... then you should just plug that new slope into point-slope form or slope-intercept form to get your equation... y-y1 = m(x-x1) ... y-1= (3/4)(x-1) ... so it would be y=(3/4)x + 1/4 then for part f just convert into standard form which is just manipulating the variables... look up standard form equation on Google and manipulate the variables from there.