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podryga [215]
2 years ago
11

The radioactive substance uranium-240 has a half-life of 14 hours. The amount

Mathematics
1 answer:
k0ka [10]2 years ago
6 0
<h2>Answer:</h2>

See analyris

<h2>Step-by-step explanation:</h2>

Hlug\ in\ the\ value\ of \left.\ t.\right\}

The\ infital\ ampunt\ in\ the\ sample:

t=0_{-1}\ \ \ \ \ f(t)=39\omega\bullet(\frac{1}{2})^\frac{0}{14}

                        =3900\ g.

Ater\ bo\ busis.

t=6,\ \ \ \ \ A(t)=2900\times(\frac{1}{2})^\frac{60}{14}

                       =3900\times(\frac{1}{2})^\frac{30}{7}

                       \approx 209.

<em>I hope this helps you</em>

<em>:)</em>

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goldfiish [28.3K]

Answer:

LEts start with 10^1

If we have positive exponent then we add zeros

10^1= 10

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10^3=1000 (Put 3 zeros because exponent is 3)

10^4=10000 (Put 4 zeros because exponent is 4)

10^5=100000 (Put 5 zeros because exponent is 5)

For negative exponent , we make a fraction . we put 1  at the top always and number as the bottom

10^{-1}=\frac{1}{10} (Put 1 zero at the bottom because exponent is -1)

10^{-2}=\frac{1}{100} (Put 2 zeros at the bottom because exponent is -2)

10^{-3}=\frac{1}{1000} (Put 3 zeros at the bottom because exponent is -3)

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3 years ago
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aleksandr82 [10.1K]

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Step-by-step explanation:

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Harlamova29_29 [7]

Answer: First, injective means that for every y, there is only one x such f(x) = y, and surjective means that if f is a function that goes from the set {x} to the set {y}, for every element y in the codomain there is at least one element x in the domain such f(x) = y

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The function is not injective, because f(-2) = f(2), and is surjective, because the codomain is +R, and x^{2} is always a positive real number.

(b) f:N----> + N given by f(n) = n2  (i guess you written n^{2})

As the naturals have no negative numbers, in this case the function is injective, but isn't surjective, because there is no number that when squared is equal to 5, for example.

(c) f: Zx Z → Z given by f(n, k) = n +k:

here the domain is of the form (n,k) and the function is n +k, so the numbers (z,w) and (w,z) return the same value when evaluated in f, then f is not injective. And is easy to see that f is surjective, because in the sum you can reach al the integers on the codomain.

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Step-by-step explanation:

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