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Harrizon [31]
3 years ago
7

Using the formula, solve for c, if a = 9 and b = 40

Mathematics
1 answer:
alisha [4.7K]3 years ago
5 0

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

c² = a² + b²

a = 9 , b = 40

Substitute the values of a and b into the equation and solve

That's

{c}^{2}   =  {9}^{2}  +  {40}^{2}  \\  {c}^{2}  = 81 + 1600 \\  {c}^{2}  = 1681 \\ c   = \sqrt{1681}

We have the final answer as

<h3>c = 41</h3>

Hope this helps you

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Determine mu Subscript x overbar and sigma Subscript x overbar from the given parameters of the population and the sample size.
Veronika [31]

Answer:

Step-by-step explanation:

i  am sorry i do not know the

answer

3 0
3 years ago
If 1=3 2=3 3=5 4=4 5=4 then 6=?​
Mama L [17]

The value of the 6 is 3.

If you write 1 in word then you will write one and if you count the letter it will give you 3

Similarly, if you write the numbers 2,3,4,5 in word and count the number you will get 3,5,4,4 respectively.

<h3>What are the counting letters?</h3>

counting Letters provides a perfect way to introduce number words to beginning readers, as well as discuss the concepts of letters and words.

So, if you write 6 in words you will write six and on counting the letter you will get 3.

Hence, 6 = 3 ans.

Therefore the value of the 6 is 3.

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8 0
2 years ago
A rectangular playground is 10m longer than it is wide.The area of the playground is 1400m² Calculate the width and length of th
Bezzdna [24]

Answer:

1400 = x(x+10)= x^2 +10x

We can rewrite this expression like this:

x^2 +10 x -1400 =0

And we can use the quadratic formula given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where a =1 , b=10 , c= -1400

And replacing we got:

x = \frac{-10 \pm \sqrt{10^2 -4(10)(-1400)}}{2*1}

And solving we got:

x_1 =32.75 , x_2 = -42.75

And since the value can't be negative the answer would be x = 32.75 and the value of y = 32.75+10 =42.75

Step-by-step explanation:

For this case we know that we have a rectangular playground and the area can be founded with this formula:

A = xy

Where x represent the width and y the length. From the problem we know that A =1400 m^2 and the heigth is 10m longer than the wide so we can write this condition as:

y = 10 +x

And replacing this formula into the area we got:

1400 = x(x+10)= x^2 +10x

We can rewrite this expression like this:

x^2 +10 x -1400 =0

And we can use the quadratic formula given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where a =1 , b=10 , c= -1400

And replacing we got:

x = \frac{-10 \pm \sqrt{10^2 -4(10)(-1400)}}{2*1}

And solving we got:

x_1 =32.75 , x_2 = -42.75

And since the value can't be negative the answer would be x = 32.75 and the value of y = 32.75+10 =42.75

8 0
3 years ago
Read 2 more answers
Help ASAP please please please
Andre45 [30]

Answer:

3 is between 1 and 2 so A. will be the correct answer

1 x 1 = 1

2 x 2 = 4

Hope this helps

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I’ll mark u brain if u help me
ZanzabumX [31]

Answer:

x-1=y or y+1=x

Step-by-step explanation:

I think thats right,

5 0
3 years ago
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