Question

PLEASE HELP!!!!!!!!!!!!!!!!!

Answer 1

The answer is 2 3/10. how do you not know this

Answer 2

Answer:

Hence, the number of hours he did work on both days is:

$2\dfrac{3}{10}hour$

Step-by-step explanation:

It is given that:

Clay worked $1\dfrac{1}{5}hour$ yesterday.

i.e. in simple fraction the number of hours he worked yesterday is:

$1\dfrac{!}{5}=\dfrac{1\times 5+1}{5}=\dfrac{6}{5}hours$

He worked $1\dfrac{1}{10}hour$ today.

i.e. the number of hours he worked today in simple fraction terms is:

$1\dfrac{1}{10}=\dfrac{1\times 10+1}{10}=\dfrac{11}{10}hours$

The number of hours he worked on both days is:

Number of hours he worked yesterday+Number of hours he worked today.

$=\dfrac{6}{5}+\dfrac{11}{10}=\dfrac{6\times 2+11}{10}=\dfrac{12+11}{10}=\dfrac{23}{10}$

which could also be represented as:

$2\dfrac{3}{10}hour$

Hence, the number of hours he did work on both days is:

$2\dfrac{3}{10}hour$