Question

If m and n are whole numbers such that m^n = 121, then find the value of (m-1)^n+1.​

Answer 1

Because m and n are whole numbers, we only have 3 values for m, and 3 values for n :

$1^{121} ; 11^{11} ;121^{1}$ (or you can say because 121 only have the factors of 1 ; 11 ; 121, those are the only possible values for m and n, then conclude the possible values)

Now, we will substitute them in :

If m = 1 ; n = 121

$(1-1)^{121+1}$ = 0

If m = 11 ; n = 11

$(11-1)^{11+1}$ = 1000000000000

If m = 121 ; n = 1

$(121-1)^{1+1}$ = 14400