Answer and Step-by-step explanation:
Team: Points. Results fetching points
Arcadia. 3+1. 1 win & 1 draw
Brextone. 3+1. 1 win & 1 draw
Cremore 1+1. 2 draws
Dunross. 3+3. 2 wins
a) Based on the previous data, we can conclude that the number of matches drawn was 4
b) Dunross defeated cremore since cremore did not win any league game and dunross reported no ties
c) Yes, you can get a prediction of the matches with their respective results as follows
Brextone drew with Cremore
Dunross beat Arcadia
Arcadia beat Brextone
Arcadia drew with Cremore
Dunross beat Cremore
Answer:
318125267
Step-by-step explanation:
-_-...............that is the answer
The measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.
<h3>what is measure centre and measure of variation? </h3>
A measure of central tendency (measure of centre) is a value that attempts to describe a set of data by identifying the central position of the data set.
The measure of central tendency includes the mean, median and mode.
The measure of variation describes the amount of variability or spread in a set of data.
The common measures of variability are the range, the interquartile range (IQR), variance, and standard deviation.
Therefore, the measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.
learn more on measure of centre and variation here: brainly.com/question/23769503
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Answer:
y/x = 2.5
Step-by-step explanation:
y ∝ x
change ∝ to = by adding constant k or c
y = kx
Divide both sides by x
y/x = k, also k = y/x
Input the values
k = (7 1/2)/3. Change 7 1/2 to improper fraction to give 15/2
k = (15/2)/3
k = 
÷ 3
Change the division sign to multiplication which will change 3 to its inverse(1/3)
k = × 
k = 
Divide the numerator and denominator by 3 to get 5/2
k = 5/2
From y/x = k,input k into the eqn
y/x = 5/2
y/x = 2.5
Answer:
2ab(3b^2+2a+4)
Step-by-step explanation:
6ab^3 + 4a^2b + 8ab
2*3*a*b*b^2 +2*2*a*a*b +2*2*2*a*b
Factor out the common terms
2ab( 3*b^2 +2*a +2*2)
2ab(3b^2+2a+4)
