Ask question

Ask question

All categories

3 years ago

8

Mohamed surveyed his class on their favorite candy bar. 8 picked Snickers. 6 picked Kit Kats. 6 picked Milky Ways. If he applied

the results of his survey to the whole school of 1500 people, about how many students would choose Snickers?

1 answer:

Gnom [1K]3 years ago

3 0

Answer:

600:450:450

Step-by-step explanation:

8+6+6= 20

1500/20=75

8*75= 600

6*75= 450

6*75=450

Check:

600/75= 8

450/75= 6

450/75=6

You might be interested in

Three consecutive even integers have a sum of -126. What is the smallest integer ?

SSSSS [86.1K]

Answer:

-40, - 42 and -44

Step-by-step explanation:

The fastes way here is trying. Lets pick a number, intelligently, and then work on it.

We need three even integers that sum -126. These will be all negative numbers and as they are consecutive they will be very similar (for example, -33 and -35 and -37). Thus, lets start by 1/3 of -126, which is -42:

(-42)+ (-44) + (-46) = - 132, so -42 no.

Lets go a step back: -40

(-40) + (-42) + (-44) = -126

So, the integers are -40, -42 and -44

5 0

3 years ago

What y=Mx+b <br>A, a slope formula<br>B, math<br>C, y-intercept

FinnZ [79.3K]

Answer:

Slope-intercept form

Step-by-step explanation:

The correct answer is actually slope-intercept form.

6 0

3 years ago

Read 2 more answers

Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required

xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

$A = Pe^{rt}$

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

A = 2 × $3000

A = $6000

$6000 = 3000e^{0.085t}$

$\frac{6000}{3000} = e^{0.085t}$

$2 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}2 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln2 = 0.085t$

$t = \frac{ln2}{0.085}$

$t = \frac{0.693}{0.085}$

t = 8.15

(b) For the amount to double, A = 3 × P

A = 3 × $3000

A = $9000

$9000 = 3000e^{0.085t}$

$\frac{9000}{3000} = e^{0.085t}$

$3 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}3 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln3 = 0.085t$

$t = \frac{ln3}{0.085}$

$t = \frac{1.0986}{0.085}$

t = 12.92

5 0

3 years ago

Six less than 2 times “y” is 34 equation form

wel

2y-6=34 is the needed equation

8 0

3 years ago

Read 2 more answers

Compare the fraction 1:24,000 to the fraction 1:3,168,000; which is the largest rational number

gulaghasi [49]

Answer:

$\frac{1}{24,000}$

Step-by-step explanation:

we know that

When we compare positive fractions with the same numerator, the largest rational number will be the fraction with the lowest denominator

In this problem we have

$\frac{1}{24,000}$ and $\frac{1}{3,168,000}$

Both numerator are equal

Compare the denominators

$24,000 < 3,168,000$

therefore

$\frac{1}{24,000}$ is the largest rational number

7 0

3 years ago