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ankoles [38]
3 years ago
8

Mohamed surveyed his class on their favorite candy bar. 8 picked Snickers. 6 picked Kit Kats. 6 picked Milky Ways. If he applied

the results of his survey to the whole school of 1500 people, about how many students would choose Snickers?
Mathematics
1 answer:
Gnom [1K]3 years ago
3 0

Answer:

600:450:450

Step-by-step explanation:

8+6+6= 20

1500/20=75

8*75= 600

6*75= 450

6*75=450

Check:

600/75= 8

450/75= 6

450/75=6

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Answer:

lenght = 2x + 3

breadth = x - 1

perimeter = 40

Now,

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40= 2( 2x + 3 + x - 1)

40= 2(3x - 2)

40 = 6x- 4

40+4 =6x

44/6 =x

x = 7.33

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2 years ago
Question 5
baherus [9]

9514 1404 393

Answer:

  A. no solution

Step-by-step explanation:

The solution is found where the lines meet. Parallel lines never meet, so there is no solution.

7 0
2 years ago
When you multiply and divide by a negative you have to _______​
Molodets [167]

Answer:

Multiplying and dividing with integers. You also have to pay attention to the signs when you multiply and divide. There are two simple rules to remember: When you multiply a negative number by a positive number then the product is always negative.

Step-by-step explanation:

8 0
3 years ago
The cost to repair linda's car is $500, including parts and labor. the cost of parts is $140. if the cost of labor is $40 per ho
Mkey [24]
500=140+40h
minus 140 both sides
360=40h
divide y 40
9=h
9 hours
5 0
3 years ago
I really need help! This is last minute and its 1 am. I'm tired so I'm going to leave it to you guys to solve my problems and pr
Illusion [34]

Answer:

<h2><u>question 1</u></h2>

n^{2} - 20n -96 = 0

use product and sum method

product = -96

sum = -20

numbers needed = ( -24 , 4)

n - 24 = 0

n + 4 = 0

hence <u>n = 24 and n = -4 </u>

<u></u>

<h2><u>Question 2 </u></h2>

<u />x^{2} + 12 x = 48<u />

in the form ax^{2}  +bx +c = 0

= x^{2} +12x - 48

make use of the formula :

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

replace values to make 2 equations :

1.\frac{-12+\sqrt{12^{2} -4*1*-48} }{2*1} = 3.17

2.\frac{-12-\sqrt{12^{2} -4*1*-48} }{2*1} = -15.2

hence <u>x = 3.17 and x = -15.2</u>

<u />

<h2><u>Question 3 </u></h2>

<u />x^{2} -14x+40=0<u />

use product and sum method

product = 40

sum = -14

numbers needed = (-10 , -4)

x - 10 = 0

x - 4 = 0

hence<u> x = 10 and x = 4</u>

<u />

<h2><u>Question 4 </u></h2>

<u />5b^{2} -20b-18 = 7<u />

in the form ax^{2}  +bx +c = 0

this becomes 5b^{2} -20b-18-7

= 5b^{2} -20b-25

can simplify by 5

= b^{2} -4b-5 =0\\

use product and sum method

product = -5

sum = -4

numbers needed (-5 , 1)

b-5 = 0

b + 1 = 0

hence <u>b = 5 and b = -1</u>

5 0
3 years ago
Read 2 more answers
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