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ankoles [38]
3 years ago
8

Mohamed surveyed his class on their favorite candy bar. 8 picked Snickers. 6 picked Kit Kats. 6 picked Milky Ways. If he applied

the results of his survey to the whole school of 1500 people, about how many students would choose Snickers?
Mathematics
1 answer:
Gnom [1K]3 years ago
3 0

Answer:

600:450:450

Step-by-step explanation:

8+6+6= 20

1500/20=75

8*75= 600

6*75= 450

6*75=450

Check:

600/75= 8

450/75= 6

450/75=6

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3. Subtract 8.263 from 13.48. A. 21.743 B. 5.217 C. 5.783 D. 6.815
nikdorinn [45]
8.263-13.48= -5.217
But
13.48-8.263= 5.217
So if there's no negative answer choices then the answer is B. 5.217 :) hope this helped
8 0
3 years ago
Simplify -|-5 + 2|.
qwelly [4]
Hello,

The answer will be "-5+2".

Reason:

I These lines turn negative numbers into positive:

Therefore the answer will be -5+2 (since how the first - sign was outside of the I).

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
7 0
3 years ago
6w=30 for w=5 please help me with this
Bond [772]
6(5)=30
6 times 5 is 30
7 0
4 years ago
Read 2 more answers
Find the slope, or rate of change, from the graph. <br><br> answer please correct answers
Vaselesa [24]

Answer:

3/2

Step-by-step explanation:

slope is rise over run

or y change divided by x change

to find the slope you need to find points on the graph that meet exact points on the graph

i see (0,0) and (4,6)

to find slope without graph it would be (y2-y1)/(x2-x1)

in this case (6-0)/(4-0)

=6/4

=3/2

=1  1/2

with graph you can count that it goes up 3 squares while moving two squares to the right

3/2

hope this helps

3 0
3 years ago
Give the equivalent numerator if the denominator is x³y².
gayaneshka [121]
x³y²
 For this case, the first thing you should know is the properties of the exponents.
 Let's write the full fraction:
 (1) / (x ^ 3 * y ^ 2)
 We have that by power properties:
 (1) / (x ^ 3 * y ^ 2) = x ^ -3 * y ^ -2
 Therefore the equivalent numerator is:
 x ^ -3 * y ^ -2
 Answer:
 x ^ -3 * y ^ -2
7 0
3 years ago
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