Answer:
I'll set up the problem and you can do the calculation
Step-by-step explanation:
we need to complete the squares to get the equation in the general form:
where h = the x coordinate of the center
k = the y coordinate of the center
r = the radius
so looking at
we can see that if use -1 as the constant we have
doing the same for y
we can use -2 as the constant (basically you that the s
quare of the y coefficient )
so now we have to add or subtract the constant on the RHS to see what the square of the radius is according to the general form of the equation at the top
20 +1+4=25
Take the square root and you have the radius
Answer:
I think it's all of them :)
Answer:
3/2, -3/2, (if it is asking for imaginary solutions as well then 3i/2 and -3i/2)
Step-by-step explanation:
1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
I believe the answer is 15 because if you divide 270/18 you get 15 <span />
