Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
Total number of different tickets are possible is


Therefore, 4032 different tickets are possible.
Two vertical angles are formed. These angles are also equal to each other.
Answer:
I think it's line "A"
Step-by-step explanation:
It’s 29
The chicken is 20
The eggs are 3
And the bananas are 6
longest leg = 2
The longest leg is opposite the 60° angle
= 4 × sin60°
= 4 ×
/ 2 = 2